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Tanzania [10]
3 years ago
15

Solve the system of linear equations below.

Mathematics
2 answers:
Olegator [25]3 years ago
5 0

Answer:

B. x = 2, y = 6

Step-by-step explanation:

2x + 5y = 34...(1) \\  \\ x + 2y = 14 \\  \therefore \: x = 14 - 2y...(2) \\  \\ from \: equations \: (1) \: and \: (2) \\  \\ 2(14 - 2y) + 5y = 34 \\ \therefore \: 28 - 4y + 5y = 34 \\  \therefore \: 28 + y = 34 \\ \therefore \:  y = 34 - 28 \\  \huge \red{ \boxed{\therefore \:  y = 6}} \\ substituting \: y = 6 \: in \: equation \: (2) \\ x = 14 - 2 \times 6 \\ \therefore \:  x =14 - 12 \\  \huge \purple{ \boxed{\therefore \:  x =2}} \\  \\ \huge \orange{ \boxed{ \therefore \:  x  = 2, \:  \: y = 6}} \\

yulyashka [42]3 years ago
3 0

Answer: x=2, y=6: correct answer is B

Step-by-step explanation:

2x+5y=34............(1)

x+2y=14..............(2)

Using substitution method

Make x the subject of formula in equation 2

x=14-2y................(3)

Substitute equation 3 into equation 1

2(14-2y)+5y=34

28-4y+5y=34

28+y=34

Make y the subject of the formula

y= 34-28

y=6

To find x substitute y=6 into equation 1

2x+5y=34

2x+5(6)=34

2x+30=34

2x=34-30

2x= 4

x=4/2

x=2

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0.9 (15) - 1.5 (3)

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Note:

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3 0
3 years ago
Evaluate the given expression for x = 3 and y = 2.
kumpel [21]

Answer:

11

Step-by-step explanation:

3(2) - (3(3) + 2) + 16

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4 0
2 years ago
Find the value of h(-67) for the function below.
pshichka [43]

Answer:

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Step-by-step explanation:

<u>Given function:</u>

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5 0
3 years ago
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The average speed of one team in a relay is about 5 miles per hour what is this speed in feet per second round to the nearest te
lisov135 [29]
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8 0
3 years ago
Solve this equation.
Anika [276]

Answer:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal

Step-by-step explanation:

Solve for b:

b - (3 + 2/5) = 8 + 1/5

Put 3 + 2/5 over the common denominator 5. 3 + 2/5 = (5×3)/5 + 2/5:

b - (5×3)/5 + 2/5 = 8 + 1/5

5×3 = 15:

b - (15/5 + 2/5) = 8 + 1/5

15/5 + 2/5 = (15 + 2)/5:

b - (15 + 2)/5 = 8 + 1/5

15 + 2 = 17:

b - 17/5 = 8 + 1/5

Put each term in b - 17/5 over the common denominator 5: b - 17/5 = (5 b)/5 - 17/5:

(5 b)/5 - 17/5 = 8 + 1/5

(5 b)/5 - 17/5 = (5 b - 17)/5:

(5 b - 17)/5 = 8 + 1/5

Put 8 + 1/5 over the common denominator 5. 8 + 1/5 = (5×8)/5 + 1/5:

(5 b - 17)/5 = (5×8)/5 + 1/5

5×8 = 40:

(5 b - 17)/5 = 40/5 + 1/5

40/5 + 1/5 = (40 + 1)/5:

(5 b - 17)/5 = (40 + 1)/5

40 + 1 = 41:

(5 b - 17)/5 = 41/5

Multiply both sides of (5 b - 17)/5 = 41/5 by 5:

(5 b - 17)/(5 1/5) = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 1/5×1/(1/5) 41

1/5×1/(1/5) = 1:

5 b - 17 = 41

Add 17 to both sides:

5 b + (17 - 17) = 17 + 41

17 - 17 = 0:

5 b = 41 + 17

41 + 17 = 58:

5 b = 58

Divide both sides of 5 b = 58 by 5:

(5 b)/5 = 58/5

5/5 = 1:

Answer:  b = 58/5  or 11 3/5 or 11.6 decimal


5 0
3 years ago
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