Answer:

Explanation:
We are given that a parallel- plate capacitor is charged to a potential difference V and then disconnected from the voltage source.
1 m =100 cm
Surface area =S=


We have to find the charge Q on the positive plates of the capacitor.
V=Initial voltage between plates
d=Initial distance between plates
Initial Capacitance of capacitor

Capacitance of capacitor after moving plates


Potential difference between plates after moving








Hence, the charge on positive plate of capacitor=
The example of the scientific practice is missing here but it should always involve the application of the scientific method.
<h3>What is the scientific method?</h3>
The scientific method is a series of steps by which researchers can collect empirical evidence that enables them to test hypotheses and generate scientific theories.
The scientific method starts with the observation of a given phenomenon from the real world, which then enables the raising of a question that in turn enables the formulation of a plausible explanation called hypothesis.
In conclusion, the example of the scientific practice is missing here but it should always involve the application of the scientific method.
Learn more about the scientific method here:
brainly.com/question/17216882
#SPJ1
Answer:
<em>The internal energy change is 330.01 J</em>
Explanation:
Given
the initial volume = 5.75 L
the final volume = 1.23 L
is the external pressure = 1.00 atm
q the heat energy removed = -128 J (since is removed from the system)
expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;
W = -
ΔV
W = -1.00 x(1.23 - 5.75)
W = -1.00 x -4.52
W = 4.52 L atm
converting to joules we have
W = 4.52 L atm x 101.33 J/ L atm = 458.01 J
The internal energy change during compression can be calculated thus;
ΔU = q + W
ΔU = -128 J + 458.01 J
ΔU = 330.01 J
Therefore the internal energy change is 330.01 J