Centripetal Force, F = mv²/r
Where m = mass in kg, v = velocity in m/s and r = radius of curvature in m.
Centripetal Force, F = 2000 * 25² / 80. Use your calculator.
F = 15 625 N.
Answer:
the force of friction = fk = (uk)n = 402(uk)
the net force acting to accelerate bookcase = ma = (41)(0.12) = 4.9 N
the {assumed horizontal} push force = 65 N
so
65 - fk = 4.9
fk = 65 - 4.9 = 60 N
uk = 60/402 = 0.15 <= ANS
The correct answer is
<span>c the friction force from the road
In fact, the friction force between the road and the tires prevents the car from "sliding away" in a straight line and keeps it in circular motion, acting as centripetal force.</span>
