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Serggg [28]
3 years ago
15

A person in a kayak starts paddling, and it accelerates from 0 to 0.65 m/s in a distance of 0.40 m. If the combined mass of the

person and the kayak is 75 kg, what is the magnitude of the net force acting on the kayak?
Physics
1 answer:
SCORPION-xisa [38]3 years ago
6 0

Answer:

Magnitude of the net force acting on the kayak = 39.61 N

Explanation:

Considering motion of kayak:-

Initial velocity, u =  0 m/s

Distance , s = 0.40 m

Final velocity, v = 0.65 m/s

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    0.65² = 0² + 2 x a x 0.4

    a = 0.53 m/s²

We have force, F  = ma

Mass, m = 75 kg

    F  = ma = 75 x 0.53 = 39.61 N

Magnitude of the net force acting on the kayak = 39.61 N

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Why do heavier objects fall at the same speed as lighter ones?
GaryK [48]
Speed of any freely falling object is always same. Provided, both are left to fall from the same height. If you perform this experiment in a perfect vacuum or near vacuum laboratory, both of them will reach ground with same velocity this is because there is no resistance to their motion. This is always true no matter where you go and perform this experiment. 
It can be easily proved from conservation of mechanical energy. Why conserving energy? because there are no forces acting on the freely falling objects other than conservative force(mg). 

5 0
4 years ago
What is electricity?
ASHA 777 [7]

Answer:

The flow of electric charge

Explanation:

Electricity:It is defined flow of electric charge.

It is defined as the flow of charge per unit time.

Electric charge can be negative or positive .

Mathematical representation :

If charge Q flowing through the conductor and time taken in flow of charge is t seconds.

Then, current=I=\frac{Q}{t}

S.I unit of current is Ampere.It is scalar quantity.

Answer:The flow of electric charge.

8 0
3 years ago
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
OlgaM077 [116]

Answer:

On moon time period will become 2.45 times of the time period on earth

Explanation:

Time period of simple pendulum is equal to T=2\pi \sqrt{\frac{l}{g}} ....eqn 1 here l is length of the pendulum and g is acceleration due to gravity on earth

As when we go to moon, acceleration due to gravity on moon is \frac{1}{6} times os acceleration due to gravity on earth

So time period of pendulum on moon is equal to

T_{moon}=2\pi \sqrt{\frac{l}{\frac{g}{6}}}=2\pi \sqrt{\frac{6l}{g}} --------eqn 2

Dividing eqn 2 by eqn 1

\frac{T_{moon}}{T}=\sqrt{\frac{6l}{g}\times \frac{g}{l}}

T_{moon}=\sqrt{6}T=2.45T

So on moon time period will become 2.45 times of the time period on earth

5 0
3 years ago
There are great similarities between electric and gravitational fields. A room can be electrically shielded so that there are no
ella [17]

Answer:

Can a room be gravitationally shielded? No, it can't.

Explanation:

the room cannot be gravitationally shielded because there is only one gravitational charge, in this case is mass. Mass can always be positive. the room can be electrically shielded because there are two type of charge, positive and negative charge than can cancel each other out.

7 0
3 years ago
A car starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds. What is its acceleration? What is the car’s displacement? (Demons
disa [49]

The acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².

<h3>How to calculate acceleration?</h3>

The acceleration of a moving object can be calculated using the following formula:

a = (v - u)/t

Where;

  • a = acceleration (m/s²)
  • v = final velocity (m/s)
  • u = initial velocity (m/s)
  • t = time (s)

According to this question, a car starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds.

a = (25.5 - 12.5)/5

a = 13.0/5

a = 2.6m/s²

Therefore, the acceleration of a car that starts at 12.5 m/s and reaches 25.5 m/s in 5.00 seconds is 2.6m/s².

Learn more about acceleration at: brainly.com/question/12550364

#SPJ1

4 0
2 years ago
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