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Serggg [28]
4 years ago
15

A person in a kayak starts paddling, and it accelerates from 0 to 0.65 m/s in a distance of 0.40 m. If the combined mass of the

person and the kayak is 75 kg, what is the magnitude of the net force acting on the kayak?
Physics
1 answer:
SCORPION-xisa [38]4 years ago
6 0

Answer:

Magnitude of the net force acting on the kayak = 39.61 N

Explanation:

Considering motion of kayak:-

Initial velocity, u =  0 m/s

Distance , s = 0.40 m

Final velocity, v = 0.65 m/s

We have equation of motion v² = u² + 2as

Substituting

   v² = u² + 2as

    0.65² = 0² + 2 x a x 0.4

    a = 0.53 m/s²

We have force, F  = ma

Mass, m = 75 kg

    F  = ma = 75 x 0.53 = 39.61 N

Magnitude of the net force acting on the kayak = 39.61 N

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On earth, the solar constant is approximately I = 1367 W/m2 . This corresponds to the power per unit area that a detector at the
d1i1m1o1n [39]

Answer:

Explanation:

for earth -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₁²  x solar constant on earth , R₁ is distance between earth and sun.

for marsh -sun system

E = σ T⁴ ,  E is radiation emitted by sun at temperature T

E = 4π R₂²  x solar constant on Mars , R₂ is distance between earth and sun.

from two equation ,

4π R₂²  x solar constant on Mars = 4π R₁²  x solar constant on earth

solar constant on Mars = (R₁ / R₂ )² x solar constant on earth

6 0
4 years ago
A radio transfers 270 j of energy electrically, 94.5 j is transferred by sound. Work out the efficiency of this radio. Give your
MakcuM [25]

Answer:

35%

Explanation:

Given data

Amount of energy transferred (Input) = 270J

Amount of energy converted to sound (Output)=  94.5J

Efficiency = output/input*100

Efficiency= 94.5/270*100

Efficiency=0.35*100

Efficiency=35%

Hence the efficiency is 35%

6 0
3 years ago
Imagine you are holding a box in your hand, the force required for you to hold the box with mass 4.54kg and you want to accelera
svetlana [45]

Answer:

(a) Fₓ = 0 N

F_y = 9.08 N

(b)

(a) Fₓ = 0 N

<u></u>F_y = 9.08 N

(c) F_y = 0 N

Fₓ = 9.08 N

Explanation:

The magnitude of the force will remain the same in each case, which is given as follows:

F = ma (Newton's Second Law)

where,

F = force = ?

m = mass = 4.54 kg

a = acceleration = 2 m/s²

Therefore,

F = (4.54 kg)(2 m/s²)

F = 9.08 N

Now, we come to each scenario:

(a)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

<u>Fₓ = 0 N</u>

For upward direction the force will be positive:

<u></u>F_y<u> = 9.08 N</u>

<u></u>

(b)

Since the motion is in the vertical direction. Therefore the magnitude of the force in x-direction will be zero:

<u>Fₓ = 0 N</u>

For upward direction the force will be negative:

<u></u>F_y<u> = - 9.08 N</u>

<u></u>

(c)

Since the motion is in the horizontal direction. Therefore the magnitude of the force in y-direction will be zero:

<u></u>F_y<u> = 0 N</u>

<u>Fₓ = 9.08 N</u>

3 0
3 years ago
If the incoming photon had a frequency of 8.0 E14 Hz, would you have a photo-electron ejected?
cupoosta [38]

Yes.


In fact, from the graph we see that the threshold frequency (the minimum energy of the incoming energy needed to extract a photoelectron from the material) is 5.0 \cdot 10^{14} Hz (we see it because this is the frequency at which the maximum kinetic energy of the emitted electron is zero).


The incoming photon in this problem has a frequency of 8.0 E14 Hz, so above the threshold frequency, therefore it is enough to extract photoelectrons from the material.

4 0
4 years ago
2. An 873 kg dragster accelerates at a rate of 44.6 m/s during a race.
Ira Lisetskai [31]

Answer:

<h3>38,673.9N</h3>

Explanation:

According to newton's second law:

Force = mass * acceleration

Given

Mass = 873kg

acceleration = 44.66m/s²

Magnitude of the force is expressed as;

F = ma

F = 873 * 44.6

F = 38,673.9N

<em>Hence the magnitude of the net force exerted on the dragster during this time is 38,673.9N</em>

8 0
3 years ago
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