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Zinaida [17]
4 years ago
10

A car starts from rest and travels 25 m in 5 seconds at constant velocity. It then reverses 5 m in 10 seconds at constant veloci

ty. The car then sits at rest for 5 seconds before it reverses at constant velocity back to where it started in 10 seconds time. Draw a position time graph that demonstrates the motion of the car.
Physics
1 answer:
natali 33 [55]4 years ago
8 0

Answer:

the car is going to same sped !

Explanation:

I just now luv

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A crumb of bread, of mass 0.056 kg, is pulled upon by ants from rival anthills. They exert the following forces: 0.06 N to the n
Valentin [98]

Answer:

a) 1.855m/s^2, 9.71\° to the east-north

b) 0.103N, 9.46° to the west-south

Explanation:

To find the acceleration of the system you can assume that  the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

0.06N-0.06Nsin(45\°)=ma_y\\\\0.08N-0.02N+0.06cos(45\°)=ma_x

m: mass of the crumb of bread = 0.056kg

you simplify the equations an replace the values of the mass in order to obtain the acceleration components:

a_y=\frac{0.017N}{0.056kg}=0.313\frac{m}{s^2}\\\\a_x=\frac{0.102N}{0.056kg}=1.829\frac{m}{s^2}

\theta=tan^{-1}(\frac{0.313}{1.829})=9.71\°\\\\a=\sqrt{a_x^2+a_y^2}=\sqrt{(1.829)^2+(0.313)^2}\frac{m}{s^2}=1.855\frac{m}{s^2}

then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north

The fifth force must cancel both x an y components of the previous net force, that is:

0.06N-0.06Nsin(45\°)+F_y=0\\\\F_y=-0.017N\\\\0.08N-0.02N+0.06cos(45\°)+F_x=0\\\\F_x=-0.102N\\\\\phi=tan^{-1}(\frac{-0.017}{-0.102N})=9.46\°

F=\sqrt{(0.102)^2+(0.017)^2}N=0.103N

the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south

4 0
3 years ago
7. Police would observe with a helicopter the time it would take for a car to travel between two wide lines placed
masya89 [10]

Answer:

See below

Explanation:

There are 3600 seconds / hr

7.2 s / 3600 s/hr = .002 hr

Car traveled 1/10 mile in .002 hr

    1/10 mi   /  .002 hr   =   50 mi/hr

5 0
2 years ago
The frequency of the middle c note on a piano is 261.63 hz. What is the wavelength of this note in centimeters? The speed of sou
Sholpan [36]

Answer:

1.31 m

Explanation:

The relationship between frequency and wavelength of a sound wave is

c=f \lambda

where

c is the speed of the wave

f is the frequency

\lambda is the wavelenfth

In this problem, we have

c = 343.06 m/s

f = 261.63 Hz

So we can solve the formula for the wavelength:

\lambda=\frac{c}{f}=\frac{343.06 m/s}{261.63 Hz}=1.31 m

8 0
3 years ago
What is the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosp
sineoko [7]

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

To find the answer, we have to know about the pressure.

<h3>How to find the weight of a column of air?</h3>
  • As we know that the expression of pressure as,

                 P=\frac{F}{A}

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.

  • It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

             P=1atm=1.013*10^5Pascals

  • From this, the value of weight will be,

            F=mg=P*A=1.013*10^5*4.5=4.56*10^5N

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.

Learn more about the pressure here:

brainly.com/question/12830237

#SPJ4

4 0
2 years ago
If acceleration of a particle at any time is given by a=2t+5 the velocity after 5 seconds, if it starts from rest is?
kow [346]
The velocity after 5 seconds is 50 m/s.
3 0
3 years ago
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