Answer:
a) 1.855m/s^2, 9.71\° to the east-north
b) 0.103N, 9.46° to the west-south
Explanation:
To find the acceleration of the system you can assume that the forces are applied in a xy plane, where force toward north are directed in the +y direction, and forces to the east in the +x direction. BY taking into account the components of the acceleration for each axis you obtain the following systems of equations:

m: mass of the crumb of bread = 0.056kg
you simplify the equations an replace the values of the mass in order to obtain the acceleration components:


then, the acceleration of the system has a magnitude of 1.855m/s^2 and a direction of 9.71\° to the east-north
The fifth force must cancel both x an y components of the previous net force, that is:


the, the force needed to reach the equilibrium has a magnitude of 0.103N and a direction of 9.46° to the west-south
Answer:
See below
Explanation:
There are 3600 seconds / hr
7.2 s / 3600 s/hr = .002 hr
Car traveled 1/10 mile in .002 hr
1/10 mi / .002 hr = 50 mi/hr
Answer:
1.31 m
Explanation:
The relationship between frequency and wavelength of a sound wave is

where
c is the speed of the wave
f is the frequency
is the wavelenfth
In this problem, we have
c = 343.06 m/s
f = 261.63 Hz
So we can solve the formula for the wavelength:

The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>
- As we know that the expression of pressure as,

where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
- It is given that, the air column is extending from earth's surface to the top of the atmosphere, thus, the pressure will be atmospheric pressure,

- From this, the value of weight will be,

Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
brainly.com/question/12830237
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The velocity after 5 seconds is 50 m/s.