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GaryK [48]
3 years ago
15

Balance the following chemical equation : C7H6O3 + C4H6O3 —> C9H8O4 + H2O

Chemistry
1 answer:
Nana76 [90]3 years ago
6 0

Answer:

7C7H6O3 + 8C4H6O3 = 9C9H8O4·H2O

Explanation:

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D) add an appropriate amount of sodium hydroxide
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Determine the mmol of both starting materials (factoring in that formic acid is not pure, but rather 88% weight/volume, or 88g/1
Oxana [17]

Solution :

Molecular      Molar Mass       Volume      Density       Mass      Moles      nmoles

formula            (g/mol)               (mL)          (g/mL)           (g)

$C_6H_8N_2$            108.14                                                    0.108      0.001          1

HCOOH           46.02                0.064          1.22     0.07808     0.0017       1.7

mmoles of o-phenylenediamine = 1 mmoles

mmoles of formic acid = 1.7 \approx 2 mmoles

From the reaction of o-phenylenediamine and formic acid, we see,

1 mmole of o-phenylenediamine reacts with 1 mmole of formic acid.

But here, 2 mmoles of the formic acid , this means that the formic acid is an excess reagent and the o-phenylenediamine is the limiting reagent here.

The amount of product depends on the limiting reagent that is o-phenylenediamine. So, 1mmole of o-phenylenediamine will give 1mmole of product.

molar mass of Benzimidazole = 118.14 g/mol

mmoles of Benzimidazole formed = 1 mmol

Mass of benzimidazole formed = molar mass x \frac{nmoles}{1000}

                                                    $=\frac{118.14 \times 1}{1000}$

                                                     = 0.11814 g

So the theoretical yield of Benzimidazole is = 0.118 g = 118mg

5 0
3 years ago
A pharmaceutical company wants to test the efficiency of its new drug production techniques so they run 3 shifts of production f
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The percentage yield of the  new production technique is 82.8%

<h3>What is the percentage yield?</h3>

Production is the procedure by which finished products are obtained form the raw materials. The production process involves the passing of raw materials through a certain procedure that involves the use of certain machines and equipment to give us the required products.

We are told in the question that there are three shifts;

Shift 1 produces 4562 grams

Shift 2 produces 5783 grams

Shift 3 produces 5247 grams

Average production from the three shifts = 4562 grams + 5783 grams +  5247 grams/3 = 5197 grams

The theoretical average yield is =  7000 grams + 7000 grams + 7000 grams/3 = 7000 grams

Now the percentage yield = actual yield/ theoretical yield * 100/1

percentage yield = 5197 grams/7000 grams * 100/1

percentage yield = 82.8%

Learn more about percentage yield :brainly.com/question/27492865

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2 years ago
Help ASAP wil give brainlist pls
olganol [36]

2A3B ---- 4A2 +  B2

It is a balancing equation right?

3 0
3 years ago
A student mixes a 10.0 mL sample of 1.0 M NaOH with a 10.0 mL sample of 1.0 M HCl in a polystyrene container. The temperature of
ElenaW [278]

Answer:

The experimental value of ΔH is -50 kJ/mol

Explanation:

<u>Step 1: </u>Data given

Volume of 1.0 M NaOH = 10.0 mL = 0.01 L

Volume of 1.0 M HCl = 10.0 mL = 0.01 L

Temperature before mixing = 20 °C

Final temperature = 26 °C

Specific heat of solution = 4.2 J/g°C

Density = 1g/mL

<u>Step 2: </u>Calculate q

q = m*c*ΔT

⇒ with m = the mass

  ⇒ 20.0 mL * 1g/mL = 20 grams

⇒  c = specific heat of solution = 4.2 J/g°C

⇒ ΔT = T2 -T1 = 26 -20 = 6 °C

q = 20g * 4.2 J/g°C * 6°C

q = 504 J

ΔHrxn = -q  ( because it's an exothermic reaction)

ΔHrxn = -504 J

<u>Step 3:</u> Calculate number of moles

Moles = Molarity * volume

Moles = 1M *0.01 L = 0.01 moles

<u>Step 4:</u> Calculate the experimental value of ΔH

ΔHrxn = -504 / 0.01 mol = -50400 J/mol = -50.4 kJ/mol

The experimental value of ΔH is -50 kJ/mol

6 0
4 years ago
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