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Kisachek [45]
3 years ago
5

HELP ME ON QUESTION 8

Chemistry
1 answer:
kiruha [24]3 years ago
3 0
16c°

Tbh I have no clue
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A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v
DaniilM [7]

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables  P, V, T, and n. An ideal gas<u> is a hypothetical gas whose pressure-volume-temperature  behavior can be completely accounted for by the ideal gas equation</u>.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

5.0 g Ne---------- <u>x= 0.25 mol Ne</u>

Now, using the ideal gas equation we calculate the volume:

pV= nRT

V= nRT ÷ p

V= (0.25 mol × 0.082 L.atm/mol.K × 308.15 K ÷ 0.37 atm

V= 17.07 L

6 0
3 years ago
You are making a map of your state in your map scale 1 cm equals 10 km if two cities are 200 km apart how many centimeters apart
Agata [3.3K]
The answer is 20 centimeters
6 0
4 years ago
What is the representative particle for potassium chloride?
ella [17]

Answer:

In both cases, that is the mass of 6.02 × 1023 representative particles. The representative particle of CO2 is the molecule, while for Na2S, it is the formula unit.

Explanation:

3 0
3 years ago
Read 2 more answers
Only do number three please help me <br><br> Vote you brainiest
grin007 [14]

Answer:

I think it would be d.

Explanation:

Because it would just keep going until a force acts on it.

5 0
3 years ago
In a titration, 25.9 mL of 3.4 x10^-3 M Ba(OH)2 neutralized 16.6 mL of HCL solution. What is the molarity of the HCL solution?
san4es73 [151]
First, We have to write the equation for neutralization:
Ba(OH)2 + 2HCl → BaCl2 + 2H2O 
so, from the equation of neutralization, we can get the ratio between Ba(OH)2 and HCl. Ba(OH)2 : HCl = 1:2 
- We have to get the no.of moles of Ba(OH)2 to do the neutralization as we have 25.9ml of 3.4 x 10^-3 M Ba(OH)2.
So no.of moles of Ba(OH)2 = (25.9ml/1000) * 3.4x10^-3 = 8.8 x 10^-5 mol
and when Ba(OH)2 : HCl = 1: 2 
So the no.of moles of HCl = 2 * ( 8.8x10^-5) =  1.76 x 10^-4 mol

So when we have 1.76X10^-4 Mol in 16.6 ml (and we need to get it per liter)
∴ the molarity = no.of moles / mass weight
                        = (1.76 x 10^-4 / 16.6ml)* (1000ml/L) = 0.0106 M Hcl

4 0
3 years ago
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