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pentagon [3]
3 years ago
9

What is the y-coordinate of the solution for the system of equations?

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
First equation is: x - y = 12
x = 12 + y

Now, substitute this in 2nd equation, 
2x - 3y = 27
2(12+y) - 3y = 27
24 + 2y - 3y = 27
-y = 27 - 24
y = -3

In short, Your Answer would be -3

Hope this helps!
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7 0
3 years ago
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
Quadrilateral ABCD is a a square and the length of BE is 6 cm.<br><br>What is the length of AC?
Aloiza [94]

The answer is: 12 centimeters.

The explanation is shown below:

1. By definition, all four sides of the square are equal and the diagonals are equal too.

2. Keeping the information above on mind, you know that AC and BD are equal:

AC=BD

3. Then, the length of BD is twice BE. So, you can calculate it as following:

BD=2BE

BD=2(6cm)\\BD=12cm

4. Therefore, the lenght of AC is:

AC=12cm

5 0
3 years ago
Answer to the question
viktelen [127]

Answer:

x = 48.

Step-by-step explanation:

If AE is 921, then EC is equivalent to that. First, you subtract 9 from 921, then divide by nineteen to get your answer: x = 48.

5 0
3 years ago
Find the perimeter of a rectangle with a length of 6x+3 and a width of -2x-5.
blsea [12.9K]
The simple way of calculating a perimeter is to add all of the sides.
For a rectangle this would equal 2 x length + 2 x width
P = 2(6x + 3) + 2(-2x - 5)
= 12x + 6 - 4x - 10
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At a higher level both the length and width must be greater than zero (= zero is a trivial rectangle)
6x + 3 > 0
6x > -3
x > -0.5

-2x - 5 > 0
2x + 5 < 0 (multiplying by -1 reverses the inequality)
2x < -5
x < -2.5

This rectangle cannot exist as x cannot be < -2.5 and > -0.5 at the same time!
8 0
3 years ago
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