The inequality is still true! If you add a number, say 5 to both sides of the following inequality, does anything change?
3 < 6
3 + 5 < 6 + 5
8 < 11
The inequality is still true. We know the statement holds for subtracting the same number because, in a way, addition and subtraction are pretty much the same operation. If I subtract 5 from both sides, I can think of it like "I add negative 5 to both sides" or something along those lines. It's kind of backwards thinking.
Answer: 10
Step-by-step explanation:
Answer: 7/8
Step-by-step explanation:
The easiest way to do this is to find a common denominator, so first we find out 2 times how much equals 8? 2x4 = 8. So with 8 being our common denominator, we have to multiple 4 to every number in the fraction 1/2. So 1x4 = (4/8) = 2x4. Then you just add the top numbers, so 4 + 3 = 7 and keep the denominator. 7/8.
Answer:
18.0
Step-by-step explanation:
Note the tenth place value (underlined and bolded): 18.<u>0</u>49
Look at the number to the direct right of the tenth place value (or the hundredth place value in this case). It is a 4.
Note the rules of rounding. If the number:
1) is 5 or greater, round up.
2) is 4 or less, round down.
In this case, it is 4, so you will round down.
18.049 rounded to the nearest tenth is 18.0
~
Answer:
- x² - 8x + 12
- x³ + 2x² - 15x - 36
- x³ -2x² - 15x
Step-by-step explanation:
#1) Find the polynomial with roots at 2 and 6
-
(x -2)(x - 6) = x² - 8x + 12
#2) Find the polynomial with a double root at -3 and another root at 4
-
(x+3)(x+3)(x-4) = (x²+6x+9)(x-4) = x³ + 2x² - 15x - 36
#3) Find the polynomial with roots 0, -3 and 5
- (x -0)(x+3)(x-5) = x(x²-2x - 15) = x³ -2x² - 15x
