Answer:
width of the rectangle=x=4in and length of the rectangle=11in
Step-by-step explanation:
Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.
Now, width=b=x and length=l=3x-1, thus
Perimeter of the rectangle= 2(l+b)
⇒
⇒
⇒
⇒
⇒
Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.
F''(x) = 6x + 8
∫f''(x) = f'(x) = 3x^2 + 8x + c1
∫f'(x) = f(x) = x^3 + 4x^2 + c1x + c2
At point (0, -2),
c2 = -2
3x - y = 2
y = 3x - 3
f'(0) = 3
c1 = 3
Therefore, the required function is
f(x) = x^3 + 4x^2 + 3x - 2
Answer:
Encourage diversity
Race
Step-by-step explanation:
Took it on Edge :)
Answer:
a=6 - isosceles triangle and special triangle 90-45-45
b= 6^2+6^2=72
sqrroot 72 = 8.48528137424