A minimum occurs where the first derivative is 0 (the tangent line is horizontal), and the second derivative is positive (concave up). The simplest example of this is a positive parabola, like y = x², which has a relative minimum at its vertex.

8 0

2 years ago

X 3x -9 +30 +24 =180

olga55 [171]

Answer:

MAMMAAAAAAA OOOooOOOoooOOO

Step-by-step explanation:

M A M M A A A A A A A O O O o o O O O o o o O O O

5 0

2 years ago

Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)

PtichkaEL [24]

Answer:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

Both the formula can be applied to the expression( $(x^{3} x^{-6} )^{2}$ ) during the first step while solving it.

Applying formula (1):

$(x^{3} x^{-6} )^{2}$

Comparing the terms of $(x^{3} x^{-6} )$ with $p^a \times p^b$

$p=x, a =3, b=-6$

$\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $(x^{-3} )^{2}$

Applying formula (2):

Comparing the terms of $(x^{3} x^{-6} )^{2}$ with $(p^a \times q^b)^c$

$p=q=x, a =3, b=-6, c=2$

$\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}$

So, $(x^{3} x^{-6} )^{2}$ is reduced to $x^6 x^{-12}$ .

So, the answers can be:

$(x^{-3} )^{2}$

$x^6 x^{-12}$

8 0

2 years ago

The length of a rectangle is 3 times the width. If the length is decreased by 4 meters and the width is increased by 1 meter, th

olga nikolaevna [1]

Good morning☕️

______

Answer:

w is the width

L is the length

p is the perimeter

w=9

L=27

___________________

Step-by-step explanation:

p=2[(L-4) + (w+1)]

⇔p=2[(3w-4) + (w+1)]

⇔p=2[4w-3]

⇔p=8w-6

⇔66=8w-6

⇔8w=72

⇔w=9

Then L=3w=27

6 0

3 years ago