Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
68 cm, 68 m is too big.
Step-by-step explanation:
Answer:
x = 50
Step-by-step explanation:
x/5 = 125/10
x * 10 = 125*4(cross multiply)
10x = 500 ( divide both sides by 10)
x= 50
55,000÷0.04
=1,375,000
55,000÷0.02
=2,750,000
2,750,000−1,375,000
=1,375,000 increase
Answer:
d
Step-by-step explanation:
perimeter add all sides