Answer:
0.256 J.
Explanation:
The formula for the energy stored in a capacitor is given as
E = 1/2CV².................... Equation 1
Where E = Energy stored in the capacitor, C = Capacitance of the capacitor, V = Voltage.
Make C the subject of the equation
C = 2E/V².................. Equation 2
Given: E = 64 mJ = 0.064 J, V = 1.5 V.
Substitute into equation 2
C = 2(0.064)/(1.5²)
C = 0.128/2.25
C = 0.0569 F.
If the capacitor where fully charged by 3.00 V.
E = 1/2CV²
Given: C = 0.0569 F, V = 3.0 V
Substitute into the equation above,
E = 1/2(0.0569)(3²)
E = 0.256 J.
Answer:
Explanation:
a )
in the regions r < R₁
charge q inside sphere of radius R₁ = 0
Applying gauss's law for electric field E at distance r <R₁
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q / ε₀ = 0 / ε₀
E = 0
Applying gauss's law for electric field E at distance R₁ < r < R₂ .
charge q inside sphere of radius R₁ = q₁
Applying gauss's law for electric field E at distance R₁ < r < R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = q₁ / ε₀
E = q₁ / 4πε₀
in the regions r> R₂
charge q inside sphere of radius R₂ = (q₁ + q₂)
Applying gauss's law for electric field E at distance r > R₂
electric flux through Gaussian surface of radius r = 4π r² E
4π r² E = (q₁ + q₂) / ε₀
E = (q₁ + q₂) /4π ε₀
b )
For electric flux to be zero at r > R₂
(q₁ + q₂) /4π ε₀ = 0
q₁ + q₂ = 0
q₁ / q₂ = - 1 .
B.
carbon dioxide molecules have more energy; therefore, the kinetic energy increases
<span>If a book is there on the table, no work is done as no distance is covered. If I hold up a book in my hand and my arm is stretched, if no work is being done, where is my energy going?</span>
true ........i really dont kno but ok hope this helps