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Flauer [41]
3 years ago
8

A sample of an unknown liquid has a volume of 24.0 mL and a mass of 6 g. What is its density? Show your work or explain how you

determined this value.
Physics
2 answers:
jek_recluse [69]3 years ago
8 0

Answer: 0.25 grams per milliliter

Explanation:

The formula to calculate the density is given by :-

\text{Density}=\dfrac{\text{Mass}}{\text{Volume}}

We are given that the volume of liquid is 24.0 mL.

Mass = 6g

Now, the density of liquid is given by :-

\text{Density}=\dfrac{6}{24}\\\\\Rightarrow\ \text{Density}=0.25\ g/ml

Hence, its density = 0.25 grams per milliliter.

adoni [48]3 years ago
3 0
I think this might be the answer let me know 0.2 g/cm^3
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A laser emits a light beam with a wavelength of 630 nm. The jet passes a liquid with a refractive index of 1.3.
muminat
The wavelength of the laser beam in the liquid is 517 nm

Brainliest?
3 0
3 years ago
The Earth revolves around the Sun once a year at an average distance of 1.50×1011m. Find the orbital radius that corresponds to
DedPeter [7]

Answer:

9.4\cdot 10^{10} m

Explanation:

We can solve the problem by using Kepler's third law, which states that the ratio between the cube of the orbital radius and the square of the orbital period is constant for every object orbiting the Sun. So we can write

\frac{r_a^3}{T_a^2}=\frac{r_e^3}{T_e^2}

where

r_o is the distance of the new object from the sun (orbital radius)

T_o=180 d is the orbital period of the object

r_e = 1.50\cdot 10^{11} m is the orbital radius of the Earth

T_e=365 d is the orbital period the Earth

Solving the equation for r_o, we find

r_o = \sqrt[3]{\frac{r_e^3}{T_e^2}T_o^2} =\sqrt[3]{\frac{(1.50\cdot 10^{11}m)^3}{(365 d)^2}(180 d)^2}=9.4\cdot 10^{10} m

3 0
3 years ago
What is the number of the lowest energy level that contains an f sublevel?. . 3. . 4. . 5. . 6
DENIUS [597]
The correct answer among all the other choices is 4. This is the number of the lowest energy level that contains an f sublevel. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
7 0
3 years ago
1. How do galaxies change over time? 2. How are galaxies created? 3. How was Hubble important to our understanding of galaxies?
VashaNatasha [74]

Hi!


1. Galaxies are constantly evolving with time, and one manner that they do this is that they change their rotation. This is apparent from the knowledge we have of initially formed galaxies which are spiral like in the beginning, but over time transform into what seems like smooth, barren disks. Another difference is that some galaxies are younger than others, and the age difference is observed with younger galaxies having a higher number of stars that are also comparatively brighter, which makes these galaxies look blue. Older galaxies contain older stars, and older stars are seen to give off red light, which is why these galaxies seem red. Galaxies also undergo various physical and chemical changes, and older galaxies are more structured.


2. Galaxies are brought into formation with the major factor being gravity. The force of gravity is responsible for attracting various stars, collapsing gas, dust clouds and other dark matter into a structured body. Over time the organization becomes more defined. So basically, a galaxy starts off as clouds of dust and stars in space, which come into proximity with other similar clouds, and their subsequent interactions shape the structure of the galaxy.


3. Edwin Hubble, also known as the 'pioneer of distant stars', has contributed to out understanding of galaxies in that he was the first person to prove the existence of galaxies other than the Milky Way, through his studies on spiral nebulae (which were formerly thought to be clouds of dust and gas, but were actually galaxies). He also established the relationship of red shift of a galaxy (recession velocity) and the distance of the galaxy from the Earth - a directly proportional relationship, which is known as the Hubble's Law.


4. The Milky Way is found to be considerably larger, about ten times, than the average dwarf galaxy being 100,000 light years across in diameter. The Milky Way is home to 200 billion stars, and with the capacity (dust and gas) to give rise to billions more. The Milky Way is the biggest galaxy in the Virgo Supercluster, and is relatively old in comparison with most other galaxies within the universe.


5. Dark matter and gravity play a role in determining the structure of the galaxy and influences the environment over time. Dark matter contributes to the mass of the galaxy, and this affects the spin of the galaxy. The more the mass of a galaxy (or more massive a galaxy) the greater would be its rotation. Gravity is the acting force that holds the components of galaxy in place, such as the dust clouds, colonies of star, gas and dark matter. Gravity influences the structure in that it exerts and inward pull on the stars, resulting in the spiral arm structure of a galaxy, which over time tends to be more eclipse like.


Hope this helps!

7 0
3 years ago
Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0
ycow [4]

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

F_c=m\frac{v^2}{r}  (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

K=\frac{1}{2}mv^2

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}

you replace this value of v in the equation (1). Also, you replace the values of r and m:

F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N

hence, the tension in the string must be T =  Fc = 764.41 N

5 0
3 years ago
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