A 250-m-wide river flows due east at a uniform speed of 2.8m/s. a boat with a speed of 8.6m/s relative to the water leaves the s
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Answer:
1.8 cm
Explanation:
= mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg
= charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C
=Potential difference through which the ion is accelerated = 215 V
= Speed of the ion
Using conservation of energy
Kinetic energy gained by ion = Electric potential energy lost
= Radius of the path followed by ion
= Magnitude of magnetic field = 0.522 T
the magnetic force on the ion provides the necessary centripetal force, hence
The number of charge drifts are 3.35 X 10⁻⁷C
<u>Explanation:</u>
Given:
Potential difference, V = 3 nV = 3 X 10⁻⁹m
Length of wire, L = 2 cm = 0.02 m
Radius of the wire, r = 2 mm = 2 X 10⁻³m
Cross section, 3 ms
charge drifts, q = ?
We know,
the charge drifts through the copper wire is given by
q = iΔt
where Δt = 3 X 10⁻³s
and i =
where R is the resistance
R =
ρ is the resistivity of the copper wire = 1.69 X 10⁻⁸Ωm
So, i =
q =
Substituting the values,
q = 3.14 X (0.02)² X 3 X 10⁻⁹ X 3 X 10⁻³ / 1.69 X 10⁻⁸ X 0.02
q = 3.35 X 10⁻⁷C
Therefore, the number of charge drifts are 3.35 X 10⁻⁷C