3 years ago

The diagram below depicts all the forces acting on an object. Use both vector resolution and vector

Physics

1 answer:

maksim [4K]3 years ago

3 0

Answer:

Explanation:

i just took the test

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How are Neptune and Uranus allke?

AnnZ [28]

Answer:

The methane gives Neptune the same blue color as Uranus.

Explanation:

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3 years ago

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An electron, tial well may be anywhere within the interval 2a. So the uncertainty in its position is Î”x= 2a. There must be a co

lapo4ka [179]

Answer:

$K = \frac{h'}{8 m \ \Delta x^2}$ K

Explanation:

The Heisenberg uncertainty principle is

Δx Δp ≥ h' / 2

h’ = $\frac{h}{2\pi }$

The kinetic energy of a particle is

K = ½ m v²

p = mv

v = $\frac{p}{m}$

substitute

K = $\frac{1}{2} \frac{p^2}{m}$

from the uncertainty principle,

Δp = $\frac{h'}{2 \ \Delta x}$

we substitute

K = $\frac{1}{2m} ( \frac{h'}{2 \ \Delta x})^2$

$K = \frac{h'}{8 m \ \Delta x^2}$

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3 years ago

T/F all compounds are molecules but NOT all molecules are compounds.

Solnce55 [7]

True because molecules don't have to be compounds but compounds have to be molecules

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3 years ago

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws. A crab with a body weigh

frez [133]

Answer:

The weight of body is 1.3040 gram.

Explanation:

Given that,

The weight y of a fiddler crab is directly proportional to the 1.25 power of the weight x of its claws.

Suppose a crab with a body weight of 1.8 gram has claws weighing 1.1 gram.

Estimate the weight of a fiddler crab with claws weighing 0.85 gram.

Determine the weight of crab body

We need to calculate the value of proportional constant

$y\propto x^{1.25}$

$y=kx^{1.25}$

$k=\dfrac{y}{x^{1.25}}$

Put the value into the formula

$k=\dfrac{1.8}{1.1^{1.25}}$

$k=1.5978$

We need to calculate the crab weight

$y=kx^{1.25}$

Here, x = 0.85 g

Put the value into the formula

$y=1.5978\times(0.85)^{1.25}$

$y=1.3040\ gram$

Hence, The weight of body is 1.3040 gram.

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4 years ago

A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8

puteri [66]

R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
-I/5=-1/8-1/V
-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
V=40/3

HEIGHT OF IMAGE/HEIGHT OF OBJECT =-V/U
HEIGHT OF IMAGE=40/3*1/-8*15/10
=-20/8
=-2.5

7 0

3 years ago