A 68-kg skydiver has a speed of 52 m/s at an altitude of 670 m above the
1 answer:
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a) Density of the liquid:
b) Weight of the liquid: 1372 N
Explanation:
Translation of the text:
<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>
<em>a) the density of the liquid; </em>
<em>b) the weight of the liquid."</em>
a)
We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as
(1)
where
is the mass of the liquid
is the mass of the vessel
We also know that the total mass M is 5 times the mass of the empty vessel, so we have:
which is the mass of the empty vessel.
Therefore, we can find the mass of the liquid only using (1):
The density of the liquid is given by
where
m = 140 kg (mass of the liquid)
V = 0.170 kL = 170 L = (volume of the liquid, which is equal to the volume of the vessel)
So we get
b)
The weight of a body is given by
where
m is its mass
g is the acceleration due to gravity
For the liquid in this problem, we have
m = 140 kg (mass)
(acceleration due to gravity)
Therefore, its weight is
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a) The work done by the tree is
b) The amount of force applied is 2880 N
Explanation:
a)
According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:
where
W is the work done on the car
m is the mass of the car
u is its initial speed
v is its final speed
For the car in this problem, we have:
m = 2000 kg
u = 12.0 m/s
v = 0 (since the car comes to a stop, after the crash)
Therefore, the work done by the tree on the car is:
The work is negative because it is done in the direction opposite to the direction of motion of the car.
b)
The work done by the tree on the car can also be rewritten as
where
F is the force applied on the car
d is the displacement of the car during the collision
In this situation, we have:
is the work done
is the displacement of the car during the collision
Solving the equation for F, we find the force exerted by the tree on the car:
Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.
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