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Anettt [7]
2 years ago
12

Crossword Puzzle

Mathematics
2 answers:
Reil [10]2 years ago
5 0

Answer:

Check Explanation

Step-by-step explanation:

Across:

2. <u>Variable</u>

A letter or symbol that is used to represent a number is called a <u>Variable. </u>A variable can take on any value in the real number system.

e.g Given x=factor of 3, x=1 and x=3.

9. <u>Solve</u>

The algebraic process you use to isolate a variable in order to find what values, numbers, etc. will make an equation true. You <u>Solve</u> the equation.

Given x+5=3

x=3-5=-2

We have isolated the variable x by solving the equation

10. <u>Subtraction Property</u> (Two words)

If a = b, then a-c=b-c. This is the <u>Subtraction Property</u> of equality.

e.g If 3=3

3-1=3-1 but 3-1\neq3-2

You must balance the equation

Down:

1. <u>Multiplication Property</u> (Two words)

If a = b, then ac = bc. This is called the <u>Multiplication Property</u> of equality.

Just like 10 accross above,

If 3=3, then 3X5=3X5 but 3X5\neq3X4

3. <u>Addition Property</u> (Two words)

If a = b, then a+c = b+c. This is called the <u>Addition Property</u> of equality.

Just like 1 above,

If 3=3, then 3+5=3+5 but 3+5\neq3+4

4. <u>Linear</u>

A function of the form f(x) = mx + b, where m and b are real numbers, is called a <u>Linear</u> function.

This is the slope-intercept form of the equation of a line where m is the gradient and b is the y-intercept.

5. <u>Division Property</u> (Two words)

The <u>Division Property</u> of equality allows you to divide both sides of an equation by the same number.

e.g \frac{6}{3}= \frac{6}{3}\: but\: \frac{6}{3}\neq \frac{6}{4}

6.<u>Linear inequality.</u> (Two words)

A mathematical sentence which contains an inequality symbol and one variable raised to the first power is called a <u>Linear inequality.</u>

e.g  3x+2<5

7. <u>Constant term</u> (Two words)

The term in a polynomial without a variable is the<u> Constant term</u>, In the polynomial x^2+5x+3, the constant term is 3.

8. <u> Coefficient</u>

The number part when a number and a variable are multiplied together in a term is called the<u> coefficient</u> of that variable.

e.g. The coefficient of x in x^2+5x+3  is 5.

Vikki [24]2 years ago
3 0

Answer:

Please read the answers below that solve the crossword puzzle about linear equations. Tested and proved offline!

Step-by-step explanation:

Across:

2. V a r i a b l e

9. S o l v e

10. S u b t r a c t i o n p r o p e r t y (Two words)

Down:

1. M u l t i p l i c a t i o n p r o p e r t y (Two words)

3. A d d i t i o n p r o p e r t y (Two words)

4. L i n e a r

5. D i v i s i o n p r o p e r t y (Two words)

6. L i n e a r i n e q u a l i t y (Two words)

7. C o n s t a n t t e r m (Two words)

8. C o e f f i c i e n t

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In the diagram triangles ABE and ACD are similar.
jolli1 [7]

Answer:

p = 7.2

q = 6.4

Step-by-step explanation:

if the triangles are similar then the side lengths must be proportional :

AC/BA = CD/BE

9/5 = p/4 cross multiply expressions

5p = 36 divide both sides by 5

p = 7.2

same goes for q

9/5 = (q+8)/8 cross multiply expressions

72 = 5(q+8) divide both sides by 5

14.4 = q+8 subtract 8 from both sides

6.4 = q

3 0
2 years ago
15 POINTS BRAINLIEST
Irina-Kira [14]

Answer:

see explanation

Step-by-step explanation:

g(x) - f(x)

x - 3 - (3x + 2) ← distribute parenthesis by - 1

= x - 3 - 3x - 2 ← collect like terms

= - 2x - 5

There are no restrictions on the domain of - 2x - 5, thus

domain is all real numbers

8 0
3 years ago
Any help if possible Thank you ❤
azamat
I believe it's 37CM, I had that question on my finals last year.
8 0
3 years ago
Read 2 more answers
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
Giving brainlist to whoever answers
never [62]

Answer:

I think the answer would be -5

Step-by-step explanation:

Sorry if its wrong

3 0
3 years ago
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