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LenaWriter [7]
3 years ago
9

The Difference Between an Alloy and an Amalgam

Chemistry
1 answer:
Delicious77 [7]3 years ago
6 0

Mixtures or combinations of various different metals or metallic substances form things called alloys. An alloy composed of mercury and other metal (or metals) forms "amalgam". When a true alloy is created, the component metals are combined together at a temperature which is greater than the melting point of all of them.

Also, it helps to remember the word "amalgamate", which means "to alloy (a metal) with mercury" according to Dictionary.com.


Hope this helped :)


(btw I'm like 3 brainliest answers away from my next rank so could you...you know... :)

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Osmosis is a special kind of diffusion where solvent particles move through a semi permeable membrane from low concentration of solute to high concentration of solute.

so it depends upon

a) how much solvent is present : More the solvent on one side of semipermeable membrane more the movement of solvent particles on the other side of membrane


6 0
3 years ago
45 The mass of an unidentified metal sphere is 133 grams. Students determine the
Lisa [10]

Answer:

D Cobalt

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2 years ago
All three of the phosphorus-fluorine single bonds in pf3 are polar. in which direction should the polarity arrows point?
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Compare and contrast the differences between plant animal cells
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Read 2 more answers
At 25°C, the equilibrium constant Kc for the reaction in thesolvent CCl4 2BrCl <----> Br2 + Cl2 is 0.141. If the initial c
ivolga24 [154]

<u>Answer:</u> The equilibrium concentration of bromine gas is 0.00135 M

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.0300 M

Initial concentration of bromine monochlorine = 0.0200 M

For the given chemical equation:

                   2BrCl\rightleftharpoons Br_2+Cl_2

<u>Initial:</u>          0.02               0.03

<u>At eqllm:</u>    0.02-2x     x     0.03+x

The expression of K_c for above equation follows:

K_c=\frac{[Br_2]\times [Cl_2]}{[BrCl]^2}

We are given:

K_c=0.141

Putting values in above equation, we get:

0.141=\frac{x\times (0.03+x)}{(0.02-2x)^2}\\\\x=-0.96,+0.00135

Neglecting the value of x = -0.96 because, concentration cannot be negative

So, equilibrium concentration of bromine gas = x = 0.00135 M

Hence, the equilibrium concentration of bromine gas is 0.00135 M

8 0
3 years ago
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