Mass O2 = = 16.832 g
<h3>Further explanation</h3>
Given
43 grams of potassium chlorate
Required
Mass of O2
Solution
Reaction
2KClO3 ⇒3O2 + 2KCl
Mol KClO3 :
= mass : MW
= 43 g : 122,55 g/mol
= 0.3509
From the equation, mol O2 :
= 3/2 x moles KClO3
= 3/2 x 0.3509
= 0.526
Mass O2 :
= 0.526 x 32 g/mol
= 16.832 g
Answer: iron
Explanation: Metals' atoms are closely bonded in a crystal lattice. In metallic bonds, the electron cloud boundaries of atoms touch each other. Many nonmetals occur as diatomic molecules. The electron clouds of these two bonded nonmetal atoms overlap .
Answer:
Explanation:
The reaction of benzoyl chloride with NH₄OH to produce benzamide is:
Benzoyl chloride + ammonia → Benzamide + NH₄Cl
Molar mass of benzoyl chloride: 140.57 g/mol. Density 1.21g/mL
Molar mass benzamide: 121.14g/mol.
To know percent yield you must know the theoretical yield of the reaction (How many grams are produced assuming a yield of 100%). Percent yield will be (Actual yield / Theoretical Yield) ₓ 100
Moles of 2.83mL of benzoyl chloride are:
2.83mL ₓ (1.21g/mL) ₓ (1mol / 140.57g) = 0.02436 moles of benzoyl chloride.
As 1 mole of benzoyl chloride produce 1 mole of benzamide (Theoretical yield), theoretical moles of benzamide produced are 0.02436. In mass:
0.02436 moles ₓ (121.14g / mol) = 2.95g of benzoyl chloride
As there are produced just 1.95, percent yield is:
(1.95g / 2.95g) ₓ 100 = 66.1%
Answer:
Explanation:
1.08kg/50.5 cm^3(1000g/kg)=21.386 g/cm^3
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