(2)(3)(2)=12⇒ D=M/V ⇒ D=94/12=7.8333(repeated) g/m³
Answer:
I will specify a value of 0.009T for the alternator’s magnetic field
Explanation:
E_peak = 14 V
d = 10cm = 0.1m, so r = 0.1/2 =0.05m
N = 250 turns
f = 1200rpm = (1200rp/m x 1m/60sec) = 20 revolutions per second
At peak performance, peak voltage is given by the equation;
E_peak = NABω
Let's make the magnetic field B the subject;
B = E_peak/(NAω)
Now we know that ω = 2πf
Thus, ω = 2π x 20 revs/s = 125.664 revs/s.
Let's convert it to the standard unit which is rad/s.
1 rev/s = 6.283 rad/s
Thus, 125.664 revs/s = 125.664 x 6.283 = 789.55 rad/s
Area (A) = πr² = π x 0.05² = 0.007854 m²
Thus, plugging in the relevant values to get;
B = 14/[(250 x 0.007854 x 789.55)] = 0.009T
The final velocity is +15.0 m/s
Explanation:
The motion of the cart is a uniformly accelerated motion (=at constant acceleration), therefore we can use the following suvat equation:

where
v is the velocity at time t
u is the initial velocity
a is the acceleration
t is the time
For the cart in this problem, we have:
u = +3.0 m/s (initial velocity)
(acceleration)
t = 8.0 s (time)
Substituting, we find the final velocity:

Learn more about accelerated motion:
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Sample:
As soon as the lightning is seen, sound travels in the air for several kilometers until it eventually reaches the observer.
By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
<h3>
Distance between q₂ and q₃</h3>
The distance between the second charge and the third charge is given as;
r = 0.3 m
<h3>Force on q₂ due to q₃</h3>

<h3>Net force on particle q₁</h3>
The net force on particle q₁ is determined by summing the individual forces together;
F(net) = F₁ + F₂
F(net) = -14.4 + 4.54
F(net) = -9.86 N
Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
Learn more about Coulomb's law here: brainly.com/question/24743340