Answer:
diameter of largest orbit is 0.60 m
Explanation:
given data
isotopes accelerates KE = 6.5 MeV
magnetic field B = 1.2 T
to find out
diameter
solution
first we find velocity from kinetic energy equation
KE = 1/2 × m×v² ........1
6.5 × 1.6 × 
= 1/2 × 1.672 × 
×v²
v = 3.5 × 
m/s
so
radius will be
radius = 
........2
radius = 
radius = 0.30
so diameter = 2 × 0.30
so diameter of largest orbit is 0.60 m
Answer:
Check the diagram from the photo
Explanation:
Answer:
c) 11.9 yr
Explanation:
The orbital period is proportional to r^(3/2) and does not depend on the satellite's mass. Any object at Jupiter position will have the same orbital period regardless of mass.
By keppler's law we know that
T^2= r^3
T= orbital time period
r= mean distance of the planet from the Sun.
clearly, The orbital period does not depend on the satellite's mass
there, the correct answer will be c= 11.9 yr.
Answer:
They can be seen from a distance of 4.372 kilometers.
Explanation:
Using the Reyligh creterion for diffraction through a circular aperture we have
where symbol's have their usual meaning
thus applying values we get
