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Hatshy [7]
3 years ago
7

a nutrition major at wright state was studying the relationship between carbohydrates (x) and calories (y). for example, a servi

ng of a particular brand of wheat pasta yielded 42 carbohydrates and 210 calories. after collecting x and y data on many kinds of foods, the student determined the slope of the regression line to be 4.0 and the y intercept to be 3.0. if a new food is tested, and the number of carbohydrates (x) is 100, what would be the predicted calories (y’)?
Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0

Answer:

The predicted calories would be 403 calories.

Step-by-step explanation:

We have a linear regression model relating y: calories with x: carbohydrates, which has a slope of 4.0 and a y-intercept of 3.0.

Then, the model equation is:

y=4.0x+3.0

With these model we can predict the calories values for any amount of carbohydrates, within the interval within which this model is valid.

If a new food is tested, and the number of carbohydrates (x) is 100, the predicted value will be:

y(100)=4.0(100)+3.0=400+3=403

The predicted calories would be 403 calories.

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Determine the effective rate for $1 for 1 year at 5.9% compounded quarterly.
kenny6666 [7]
Keeping in mind that the effective rate, is in effect the APY or Annual Percentage Yield, 

\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 5.9\%\to \frac{5.9}{100}\to &0.059\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four times}
\end{array}\to &4
\end{cases}
\\\\\\
\left(1+\frac{0.059}{4}\right)^{4}-1\implies (1.01475)^4-1 \approx 0.0603
\\\\\\
0.0603\cdot 100\implies \stackrel{\%}{6.03}
8 0
3 years ago
the percent p of the u.s. population with internet access is given by 25p-34t=1378 where t is the number of years after 1990. wh
Mashutka [201]

Answer:

  • Hence, 75.52 percent of the u.s. population had internet access in 2005.
  • After 25 years or in the year 2015 89% have internet access.

Step-by-step explanation:

the percent p of the u.s. population with internet access is given by:

25 p-34 t=1378

where t is the number of years after 1990.

  • We are asked to find  what percent of the u.s. population had internet access in 2005 i.e. we need to find the value of p after 15 years i.e. t=15.

⇒  25p-34×(15)=1378

⇒  25p-510=1378

⇒  25p=1378+510

⇒  25p=1888

⇒  p=75.52

Hence, 75.52 percent of the u.s. population had internet access in 2005.

  • Next we are asked to find in what year will 89% have internet access?

i.e. we have to find the value of t when we are given p=89

⇒  25×89-34t=1378

⇒  2225-34t=1378

⇒  2225-1378=34t

⇒  847=34t

⇒  or 34t=847

⇒  t=24.9112≈25

Hence after 25 years 89% will have internet access.

i.e. in the year 2015 89% will have internet access.



3 0
3 years ago
1. Find the mean, median, and mode of this data set.<br> 76, 74, 78, 72, 73, 80, 49, 72, 83
aliina [53]

Mean 74
Median 73
Mode 72
3 0
3 years ago
Easton enjoys playing football at recess. He spends 1/4 of an hour at recess each day. How many hours does he spend at recess in
Dmitrij [34]

Answer:


Step-by-step explanation:

1/4 multiplied by the number of days in the week

1/4 * 5

1/4 * 5/1

5/4

1 1/4

4 0
3 years ago
mr morris needs two students to help with a demonstration for her class of 12 girls and 14 boys. She randomly chooses two studen
IRISSAK [1]
The class starts out with 26 students, of whom 12 are girls and, perhaps unlike Mr Morris, are sure of it. The probability of the first random choice being a girl is 12/26. If successful, there are now 25 students left, of whom 11 are girls. The probability of a girl on the 2nd random choice is 11/25. The probability that BOTH random choices are successful is (12/26) x (11/25). That's (132/650), or about 20.31% (rounded).
6 0
3 years ago
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