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djyliett [7]
2 years ago
11

Two similar cones have radil of 6 and 1, respectively. What is the ratio of their volumes?

Mathematics
1 answer:
Viktor [21]2 years ago
5 0
There’s my answer. I hope u enjoy ir

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A distance is related to time according to the expression x = A sin(2πft), where A and f are constants. Find the dimensions of A
nika2105 [10]

Answer:

[M⁰L¹T⁰]

Step-by-step explanation:

given expression,

from the expression  x = A sin (2 π f t),

A and f are constants

dimension of A =?  

As the sine factor is dimensionless means that sine function will not have any dimension it is dimensionless.

so, remaining  

x = A sin ()

so, the dimension of x is L  

hence, the dimension of A also will be equal to L i.e [M⁰L¹T⁰]

5 0
3 years ago
What are two equivalent ratios for 8:4
Ivenika [448]
4:2 and 2:1 are equivalent ratios to 8:4
8 0
3 years ago
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In a certain function, y varies directly with x. If y = 6 when x = 8, find x when y = 9.
Hatshy [7]

If y = 6 when x = 8, then value of "x" when y = 9 is equal to 12

<u>Solution:</u>

Given that , In a certain function, y varies directly with x

And x = 8 when y = 6,

We have to find what will be the value of x when y = 9

Now, from the given information,

\begin{array}{l}{y \alpha x} \\\\ {y=c x \rightarrow(1)}\end{array}

where c is the proportionality constant

\begin{array}{l}{\text { Now, substitute } x=8 \text { and } y=6 \text { in }(1)} \\\\ {\rightarrow 8=c(6) \rightarrow c=\frac{8}{6}} \\\\ {\rightarrow c=\frac{4}{3}} \\\\ {\text { Then, }(1) \rightarrow x=\frac{4}{3} y} \\\\ {\text { So, when } y=9} \\\\ {\rightarrow x=\frac{4}{3}(9)} \\\\ {\rightarrow x=4 \times 3} \\\\ {\rightarrow x=12}\end{array}

Hence, x value is 12 when y value is 9

3 0
3 years ago
What is the output of a function when the input is 10?
Blizzard [7]
You did not give us the function
5 0
3 years ago
Easy Question, Easy Points<br><br><br>Topic: Volume<br><br><br>Focus on question 12
Sever21 [200]

Answer:

The air is .6m^3

Step-by-step explanation:

The volume of a cube is

V = s^3 where s is the side length

The volume of the tank is

V = 1^3 = 1 m^3

The volume of the water is 1 by 1 by .4

V = l*w*h

   = 1 *1*.4

   = .4 m^3

The difference must be filled by air

1- .4 = .6 m^3

The air is .6m^3

3 0
3 years ago
Read 2 more answers
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