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3 years ago

You need 1.2 moles of H2SO4 for an experiment. You weigh out 100g of this colorless syrupy liquid. Do you have enough?

1 answer:

8 0

Answer is: not enough <span>colorless syrupy liquid.
</span>n(H₂SO₄) = 1,2 mol.
M(H₂SO₄) = 2Ar(H) + Ar(S) + 4Ar(O) · g/mol.
M(H₂SO₄) = 2·1 + 32 + 4·16 · g/mol.
M(H₂SO₄) = 98 g/mol.
m(H₂SO₄) = n(H₂SO₄) · M(H₂SO₄).
m(H₂SO₄) = 1,2 mol · 98 g/mol.
m(H₂SO₄) = 117,6 g needed.
100 g is less that 117,6 g.

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What are the benefits and drawbacks to having a pouring temperature that is much higher than the metal’s melting temperature?

Mashcka [7]

Answer:

The main advantage would be that with the pouring temperature being much higher, there is very little chance that the metal will solidify in the mould while busy pouring. This will allow for moulds that are quite intricate to still be fully filled. The drawbacks, though, include an increased chance defects forming which relates to shrinkage (cold shots, shrinkage pores, etc). Another drawback includes entrained air being present, due to the viscosity of the metal being low because of the high pouring temperature.

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3 years ago

Based on table N of the reference tables what is the number of hours required for 42k (potassium -42) to undergo three half-life

skelet666 [1.2K]

The number of hours required : 37.2 hours

<h3>Further explanation</h3>

Given

⁴²K (potassium -42)

Required

The number of hours

Solution

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually, radioactive elements have an unstable atomic nucleus.

Based on Table N(attached), the half-life for ⁴²K is 12.4 hours, which means half of a sample of ⁴²K will decay in 12.4 hours

For three half-life periods :

$\tt 3\times 12.4=37.2~hours$

3 0

3 years ago

Convert 23.92inHg to Pa.

andriy [413]

Answer:

3189.07Pa

Explanation:

The conversion of 23.92mmH to Pa can be achieved in the following way:

760mmHg = 101325Pa

23.92mmHg = (23.92x101325)/760 = 3189.07Pa

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3 years ago

Read 2 more answers

he number-average molecular weight of a polypropylene is 1,000,000 g/mol. Compute the degree of polymerization.

m_a_m_a [10]

Answer:

The answer is "23765.4"

Explanation:

Motor weight average number $(\bar{M_n}) = 1000000 \frac{g}{mol}$

Poly condensation degree dependent on the average number of molecular weights is as follows:

$DP_n = \frac{\text{Mol.Wt Number Medium}}{\text{Monomer Unit Mol.Wt}}$

All monomer module, in this case, is propylene

Sunrise. Unit Wt = Mol. Propylene weight

$= \ Mol. \ Wt \ of \ C_3H_6\\\\= 3 \times 12.01 +6 \times 1.008 \ \ \frac{g}{mol}\\\\= 42.078 \frac{g}{mol}\\\\$

$DP_n = \frac{1000000}{42.078}\\\\$

$=23765.4$

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3 years ago

Why does a heating curve have horizontal plateaus at certain points during the heating process? What is happening at those point

DENIUS [597]

A <span>heating curve having horizontal plateaus at certain points during the heating process means that the process occurs at increase heating. </span>

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3 years ago