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charle [14.2K]
3 years ago
6

An 11.75 g sample of a common hydrate of cobalt(ii) chloride is heated. after heating, 9.25 g of anhydrous cobalt chloride remai

ns. what is the formula and name for this hydrate?
Chemistry
1 answer:
Irina-Kira [14]3 years ago
3 0
Hydrated salts are when salt crystals have water molecules bound. Anhydrous salts are when the water has been removed.
mass of water removed = hydrated salt - anhydrate salt 
                                       = 11.75 g - 9.25 g = 2.50 g
number of water moles  = 2.50 g / 18 g/mol = 0.139 mol 
number of cobalt (II) chloride moles = 9.25 g / 130 g/mol = 0.0712 mol 
ratio of water moles to CoCl₂ moles - 0.139 mol / 0.0712 mol = 1.95 
rounded off 2 moles of water for every 1 mol of CoCl₂
formula - CoCl₂.2H₂O
name - Cobalt(II) chloride dihydrate
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Calculate the volume in cm^3 of 325.0 dg of alcohol. Alcohol has a density of 0.785g/mL.
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Answer:
106 mL

Explanation:
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5 0
3 years ago
Calculate the mass of 2.50 mol of CH,OH(1). Show your work. Use the appropriate
Sophie [7]

Answer:

80.1 grams

Explanation:

Find the molar mass of CH3OH first by using the periodic table values.

12.011 g/mol C + (1.008*3 g/mol H) + 15.999g/mol O + 1.008 g/mol H

=32.042 so that is the molar mass

Now that you have 2.50 moles of CH3OH, you can calculate the mass in g

2.50molCH3OH * (32.042g CH3OH / 1 mol CH3OH) = 80.105

32.042g / 1 mol is the same as 32.042 g/mol

Since there are 3 sig figs in the problem (2.50 has 3 sig figs), you round to 80.1 g CH3OH

7 0
3 years ago
Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic
vekshin1
Protons : positive charge , about same mass as neutrons , in the nucleus

neutrons : no charge , about the same mass as a proton , in the nucleus

electrons : negative charge , less mass than protons and neutrons , in orbitals outside of the nucleus
8 0
3 years ago
How many atoms are in a sample of 72.8 g calcium (Ca)?
xxMikexx [17]
Atomic mass Ca = 40.078 a.m.u

40.078 g -------------------- 6.02x10²³ atoms
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72.8 x ( 6.02x10²³) / 40.078 =

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5 0
3 years ago
Read 2 more answers
How many moles are in 8.32 x 1024 molecules of CO2.
Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.32 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 13.820598...

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

6 0
3 years ago
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