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krok68 [10]
2 years ago
9

What else would need to be congruent to show that ABC = PQR by SSS?

Mathematics
2 answers:
skelet666 [1.2K]2 years ago
8 0

Answer:

b

Step-by-step explanation:

 

Harlamova29_29 [7]2 years ago
3 0
BC=QR would make it congruent
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I need the answer for a= and b=
Lerok [7]
The answer is 67 and 34!
3 0
3 years ago
What is the equation of a hyperbola with a = 1 and c = 9? Assume that the transverse axis is horizontal.
rosijanka [135]
C^2-a^2=b^2 b^2=81-36=45 x^2/36-y^2/45=1?
5 0
2 years ago
Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. A full-size lemon tree grew three times as much as
dimulka [17.4K]

Answer: the dwarf tree grew by 3 inches.

the semi dwarf tree grew by 6 inches.

the full size tree grew by 18 inches.

Step-by-step explanation:

Let x represent how much the semi-dwarf lemon tree grew.

Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. This means that the amount by which the dwarf lemon tree grew is expressed as x/2

A full-size lemon tree grew three times as much as the semi-dwarf lemon. This means that the amount by which the full-size lemon tree grew is expressed as 3x

Together, the three trees grew 27 inches. This means that

x/2 + x + 3x = 27

Cross multiplying by 2, it becomes

x + 2x + 6x = 54

9x = 54

x = 54/9

x = 6 inches

The dwarf tree grew by 6/2 = 3 inches.

The full-size lemon tree grew by 3 × 6 = 18 inches

7 0
3 years ago
Could someone help please
pogonyaev

Answer:

3.5 m/s

Step-by-step explanation

Remove brackets

d = t^2 + 0.2t + 3.3t + .66              

Combine

d = t^2 + 3.5t + .66

The initial velocity  is 3.5

3 0
2 years ago
Solve the following equation on the interval [0, 2π). tan^2x sin x = tan^2x
Alenkasestr [34]
<h3>Given</h3>

tan(x)²·sin(x) = tan(x)²

<h3>Find</h3>

x on the interval [0, 2π)

<h3>Solution</h3>

Subtract the right side and factor. Then make use of the zero-product rule.

... tan(x)²·sin(x) -tan(x)² = 0

... tan(x)²·(sin(x) -1) = 0

This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:

... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)

Then our equation becomes

... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0

... -sin(x)²/(1 +sin(x)) = 0

Now, we know the only solutions are found where sin(x) = 0, at ...

... x ∈ {0, π}

8 0
3 years ago
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