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3 years ago

Sound molecules can "stack up" in front of airplanes traveling at very high

Chemistry

2 answers:

11111nata11111 [884]3 years ago

5 0

The answer is C a combustion’s reaction

kherson [118]3 years ago

5 0

The answer is B.......

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Help me please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

dimulka [17.4K]

Answer:

Wave 2

Explanation:

Higher frequency means more energy per second, And wave 2 has higher frequesncy

please mark brainliest I’m almost at expert level

5 0

3 years ago

Read 2 more answers

The arrangement of particles is least ordered in a sample of

lora16 [44]

Answer:

The arrangement of particles is least ordered is a > c > b > d

Explanation:

Given that,

The arrangement of particles is least ordered in a sample of NaCl.

We know that,

The least ordered arrangement are.

The form of state of particle in least ordered.

So, The least ordered arrangement will be

aqua > gas > liquid > solid

The arrangement of particles is least ordered in a sample of NaCl

$NaCl(aq) > NaCl(g) > NaCl(l) > NaCl(s)$

Hence, The arrangement of particles is least ordered is a > c > b > d

4 0

3 years ago

Write the balanced equation for the combustion of isooctane to produce water vapor and carbon dioxide gas.Assuming gasoline is i

tangare [24]

Answer:

The yield is 16 moles of CO2 per 2 moles of isooctane.

The mass of CO2 is 1.15 billion tonnes

Explanation:

First we set the unbalanced equation:

$C_{8}H_{18} + O_{2} \longrightarrow CO_{2} + H_{2}O$

Now we proceed to balance the equation:

$2C_{8}H_{18} + 25O_{2} \longrightarrow 16CO_{2} + 18H_{2}O$

With the equation balanced, we see that the theoretical yield is 16 moles of CO2 per 2 moles of isooctane and we can proceed to make calculations with the following data:

$\rho _{C_{8}H_{18}}=0.69 g/mL\\Consumption: 142.86x10^{9} gal\\1gal=3785.41 mL\\M_{C_{8}H_{18}}=114.23g/mole\\M_{CO_{2}}=44.01g/mole\\$

Knowing the different relations between mass, density and molar mass, we have the following results:

$V_{C_{8}H_{18}}=5.41x10^{14}mL\\m_{C_{8}H_{18}}=3.73x10^{14}g\\n_{C_{8}H_{18}}=3.27x10^{12}mole\\n_{CO_{2}}=2.62x10^{13}mole\\m_{CO_{2}}=1.15x1015g\\m_{CO_{2}}=1.15x10^{9}tonnes$

8 0

4 years ago

In the reaction A + B C, doubling the concentration of A doubles the reaction rate and doubling the concentration of B does not

Kitty [74]

Here, the rate of reaction would be: rate = k[A]

In short, Your Answer would be Option D

Hope this helps!

6 0

4 years ago

What is the mass in grams of 1.50 X 1023 molecules of NaOH?

avanturin [10]

Answer:

a. 10.0 g

Explanation:

The molar mass of NaOH is 39.997 grams which was calculated by adding the molar mass of Sodium, Oxygen, and Hydrogen $22.990 + 15.999 + 1.008 = 39.997$ . But before we do anything with this number we must first convert $1.50 * 10^{23}$ molecules to moles. We can do this by dividing by Avogadro's number or $6.022*10^{23}$ ( $\frac{1.50*10^{23}}{6.022*10^{23}} = 0.24909$ moles). We then convert moles to grams by multiplying by the molar mass of NaOH, ( $0.24909 * 39.997 = 9.96$ grams). This is almost exactly 10 and the margin of error is likely due to the original numbers not being precise enough.

5 0

4 years ago