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Lynna [10]
3 years ago
6

PLEASE HELP!!! What are 3 types of heat energy transfer?

Chemistry
2 answers:
Vitek1552 [10]3 years ago
8 0
Convection conduction radiation plz mark brainliest :)
Klio2033 [76]3 years ago
3 0

Answer:

indirect proportion:)

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2. What is the mass of one mole of Na?
borishaifa [10]
Sodium, Atomic mass: 22.989769 g
You can see in a periodic table
5 0
3 years ago
After an electric sign is turned on, the temperature of its glass goes from 23.5°C to 65.5°C. The sign’s glass has a mass of 905
julia-pushkina [17]

The sign's glass absorbed 25466.7 J

<h3>Further explanation</h3>

Given

The temperature of glass :  23.5 °C to 65.5 °C

mass = 905 g

the specific heat capacity = 0.67 J/g °C

Required

Heat absorbed

Solution

Heat absorbed by sign's glass can be formulated :

\tt Q=m.c.\Delta T

ΔT=65.5 - 23.5 = 42

\tt Q=905\times 0.67\times 42\\\\Q=\boxed{\bold{25466.7~J}}

5 0
3 years ago
Read 2 more answers
Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
For the reaction represented by the equation Fe + H2O ® Fe2O3 + H2, how many moles of iron(III) oxide are produced from 285 g of
schepotkina [342]

Balanced equation: 2Fe + 3H2O → Fe2O3 +3H2

Convert g to mols:

285/55.845 = 5.1034 mols

Mole ratio of Iron and Iron (III) Oxide: 2:1

5.1034/2 = 2.5517 mols

8 0
2 years ago
Is ineffective collision's the answer? Please correct me if not, thank you. :)
AleksAgata [21]
Yes! You're correct! Hope this helps! :D
6 0
3 years ago
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