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wel
2 years ago
5

An aqueous solution of potassium hydroxide is standardized by titration with a 0.167 M solution of nitric acid. If 16.6 mL of ba

se are required to neutralize 27.7 mL of the acid, what is the molarity of the potassium hydroxide solution
Chemistry
1 answer:
Komok [63]2 years ago
6 0

The molarity of the potassium hydroxide solution is 0.150 mol/L.

Molar attention is a measure of the attention of a chemical species, in particular of a solute in an answer, in phrases of quantity of substance consistent with the unit extent of solution.

Molarity (M) is the amount of a substance in a sure volume of answer. Molarity is defined as the moles of a solute according to the liters of a solution. Molarity is also referred to as the molar attention of a solution.

Molarity is the wide variety of moles of solute consistent with the liter of answer. For example, in case you dissolve desk salt in water, salt is the solute, and water is the solution. One mole of sodium chloride weighs 58.44 grams. in case you dissolve 58.44 grams of NaCl in a single liter of water, you have got a one molar solution, abbreviated as 1M.

Learn more about molarity here brainly.com/question/14469428

#SPJ4

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The temperature of 6.24 L of a gas is increased from 25.0°C to 55.0°C at constant pressure. The new volume of the gas is Questio
Sphinxa [80]

Answer:

Heating this gas to 55 °C will raise its volume to 6.87 liters.

Assumption: this gas is ideal.

Explanation:

By Charles's Law, under constant pressure the volume V of an ideal gas is proportional to its absolute temperature T (the one in degrees Kelvins.)

Alternatively, consider the ideal gas law:

\displaystyle V = \frac{n \cdot R}{P}\cdot T.

  • n is the number of moles of particles in this gas. n should be constant as long as the container does not leak.
  • R is the ideal gas constant.
  • P is the pressure on the gas. The question states that the pressure on this gas is constant.

Therefore the volume of the gas is proportional to its absolute temperature.

Either way,

V\propto T.

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1}.

For the gas in this question:

  • Initial volume: V_1 = \rm 6.24\; L.

Convert the two temperatures to degrees Kelvins:

  • Initial temperature: T_1 = \rm 25.0\;\textdegree{C} = (25.0 + {\rm 273.15})\; K = 298.15\;K.
  • Final temperature: T_1 = \rm 55.0\;\textdegree{C} = (55.0 + {\rm 273.15})\; K = 328.15\;K.

Apply Charles's Law:

\displaystyle V_2 = V_1\cdot \frac{T_2}{T_1} = \rm 6.24\;L \times \frac{328.15\; K}{298.15\;K} = 6.87\;L.

7 0
4 years ago
Will mark brainly read it make sense no funny business
Korolek [52]

Answer:  mixed

compound

Explanation:

6 0
3 years ago
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Answer:

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Explanation:

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