Given:
0.607 mol of the weak acid
0.609 naa
2.00 liters of solution
The solution for finding the ph of a buffer:
[HA] = 0.607 / 2.00 = 0.3035 M
[A-]= 0.609/ 2.00 = 0.3045 M
pKa = 6.25
pH = 6.25 + log 0.3045/ 0.3035 = 6.25 is the ph buffer prepared.
We have that the the molarity of methanol in the solution is mathematically given as
Morality=7.91mol/l
<h3>
Chemical Reaction</h3>
Question Parameters:
An <u>aqueous </u><em>solution </em>of methanol (MM = 32.04 g/mol)
A molality of 8.83 m and a density of 1.15 g/mL.
Generally the equation for the is mathematically given as
where
Mass of solution=(100+282.2)
Mass of solution=1289.9
Volume=1289.9/1.15
Volume=1.115L
Therefore
Morality=8.83/1.115
Morality=7.91mol/l
For more information on Chemical Reactionvisit
brainly.com/question/11231920