Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
78
Step-by-step explanation:
Evaluate 6 (2 x^2 - 5) where x = -3:
6 (2 x^2 - 5) = 6 (2×(-3)^2 - 5)
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
6 (2×9 - 5)
Hint: | Multiply 2 and 9 together.
2×9 = 18:
6 (18 - 5)
Hint: | Subtract 5 from 18.
| 1 | 8
- | | 5
| 1 | 3:
6×13
Hint: | Multiply 6 and 13 together.
6×13 = 78:
Answer: 78
Answer:
( x^2 - 6 )^2
Step-by-step explanation:
- Find one factor
- Factor by grouping
*solution* ( x^2 - 6 )^2
Answer:
C. 30.
Step-by-step explanation:
Each cube has a volume of 1 * 1* 1 = 1 cu cm.
The answer is 30 unit cubes because 30 *1 = 30.