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Stels [109]
3 years ago
13

How can you use bar graphs to compare quantities in real life situations

Mathematics
1 answer:
devlian [24]3 years ago
8 0
You can use bar graphs to compare quantities in real life situations by comparing different amounts, ex. you might use them for comparing different prices at a coffee shops around the world or different types of dogs you see at a park on a sunny day. You can really use bar graphs for comparing anything.
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A rectangle with vertices L(3, –1), M(3, –8), N(8, –8), and O(8, –1) is reflected over the y-axis.
Katen [24]

i dont know if you can see it

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%20-%206%20%3D%205y%20-%203x" id="TexFormula1" title="2x - 6 = 5y - 3x" alt="2x - 6 = 5y - 3
Zigmanuir [339]

Answer:

( 2x - 3 ) / 5

Step-by-step explanation:

2x - 6 = 5y - 3

2x - 6 + 3 = 5y

2x - 3 = 5y

y = ( 2x - 3 ) / 5

6 0
3 years ago
In this figure, what can be concluded about the distance from point B to CD?
maxonik [38]
It is the same distance from the point A to CD
4 0
4 years ago
Read 2 more answers
What go in the blanks?
Gnesinka [82]

Answer:NUMERATORS

Step-by-step explanation:

5 0
3 years ago
Ten experts rated a newly developed chocolate chip cookie on a scale of 1 to 50. Their ratings were: 34, 35, 41, 28, 26, 29, 32,
miskamm [114]

The mean deviation of the ratings is  4.12

<em><u>Explanation</u></em>

The ratings of the ten experts are:  34, 35, 41, 28, 26, 29, 32, 36, 38 and 40

So, the mean of all ratings =\frac{34+35+41+28+26+29+32+36+38+40}{10}= \frac{339}{10}=33.9

<u>The formula for Mean deviation</u> = \sum \frac{|x_{i}- \mu|}{N} , where x_{i} is the given data from i=1 to i=10 , \mu is the mean of the data and N is the total number of data. So.....

|x_{1}-\mu |= |34-33.9|=0.1\\ |x_{2}-\mu|=|35-33.9|=1.1\\ |x_{3}-\mu |=|41-33.9|=7.1\\ |x_{4}-\mu |=|28-33.9|=5.9\\ |x_{5}-\mu |=|26-33.9|=7.9\\ |x_{6}-\mu |=|29-33.9|=4.9\\|x_{7}-\mu |=|32-33.9|=1.9\\ |x_{8}-\mu |=|36-33.9|=2.1\\ |x_{9}-\mu |=|38-33.9|=4.1\\ |x_{10}-\mu |=|40-33.9|=6.1

So, the Mean deviation =\sum \frac{|x_{i}-\mu |}{N}=\frac{0.1+1.1+7.1+5.9+7.9+4.9+1.9+2.1+4.1+6.1}{10} = \frac{41.2}{10}=4.12

4 0
4 years ago
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