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zzz [600]
3 years ago
8

Joan has 7$ less than anne. together they have $43. how much does each girl have

Mathematics
1 answer:
nevsk [136]3 years ago
3 0
43÷2=21.5
21.5-7=14.5
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If the mass of a proton is 2.34 × 10–14 grams, what is the mass of 1,000 protons?
Alex17521 [72]
Masse of 1 proton: = 2.34 x 10⁻¹⁴

masse of 1000 protons = 2.34 x 10⁻¹⁴ x 1000 or 2.34 x 10 ⁻¹⁴ x 10³ =2.34 x 10⁻¹¹
8 0
3 years ago
sarah spent a total of 10 on oranges and apples at the supet market. if she spent 3 dollars less for oranges than she did on app
beks73 [17]

Let's write 2 equations from the two statements given.

<em>Sarah spent 10 dollars on both oranges and apples</em>

<em />

Let the price of oranges be "x" and price of apples be "y", thus we can write:

x+y=10

Oranges cost 3 less than apples, thus we can say:

y-3=x

We can substitute this into the first equation and solve for y:

\begin{gathered} x+y=10 \\ y-3+y=10 \\ 2y=10+3 \\ 2y=13 \\ y=\frac{13}{2} \\ y=6.5 \end{gathered}

Thus, let's solve for x now,

\begin{gathered} x=y-3 \\ x=6.5-3 \\ x=3.5 \end{gathered}

We want the price of oranges (x), thus,

<em>Price of Oranges = $3.50</em>

3 0
1 year ago
When two lines intersect to form a 90 degree angle, these lines are called ________ lines?
zalisa [80]
When two lines intersect to form a 90 degree angle, these lines are called perpendicular lines.
5 0
3 years ago
Read 2 more answers
Can someone help me with number 10, 11, 12, 15, and 16 I don’t understand them thanks
yanalaym [24]

10)

10^2-48:6+25*3=100-8+75=167

11)

8(\frac{16}{4} )+2^2-11*3=32+4-33=3

12)

(\frac{6}{3} +4)^2:4*7=(2+4)^2:4*7=6^2:4*7=36:4*7=9*7=63

13) (your answer is incorrect)

5(9-4)^2-3^2=5*5^2-3^2=5*25-9=125-9=116

14) (your answer is incorrect)

5^2-2^2*4^2-12=25-4*16-12=25-64-12=-51

15)

(\frac{50}{5^2} )^2:4=(\frac{50}{25} )^2:4=2^2:4=4:4=1

16)

\frac{24+32+30+28}{2}-expression to represent this situation

\frac{24+32+30+28}{2}=\frac{114}{2}=57

Answer: In 1 group 57 students

/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\/\

P.S. Hello from Russia :^)

4 0
3 years ago
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
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