Can someone help me please? Can you also explain? 20 points!

Mathematics

1 answer:

Yakvenalex [24]3 years ago

3 0

Surface area will consist of:
2 triangles, 3 rectangles:

Solving for triangles:
A=1/2bh
A=1/2(120)
A=60
60*2 gives us the surface area of both triangular sides.

Solve for rectangles:
(17*20)+(8*20)+(15*20)
(340)+(160)+(300)
(800)

800+120=920
The surface area of the prism is 920 square feet

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erastova [34]

Answer:

I have no clue... I'm very sorry...

Step-by-step explanation:

4 0

2 years ago

Complete the equation of the line through (-10,-7)(−10,−7)(, minus, 10, comma, minus, 7, )and (-5,-9)(−5,−9)(, minus, 5, comma,

Tanzania [10]

Answer:

$y = -\frac{2}{5}\cdot x - 11$

Step-by-step explanation:

First, the slope is determined by using the following expression:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m = \frac{-7-(-9)}{-10 - (-5)}$

$m = -\frac{2}{5}$

The y-intercept is found by using the line equation, the slope and one point:

$y = m \cdot x +b$

$b = y - m\cdot x$

$b = -7 - \left(-\frac{2}{5}\right)\cdot (-10)$

$b = -11$

The equation of the line is:

$y = -\frac{2}{5}\cdot x - 11$

7 0

4 years ago

Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$