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ANTONII [103]
2 years ago
12

What is the strength of an electric field that will balance the weight of a proton?

Physics
1 answer:
alukav5142 [94]2 years ago
3 0

The weight (force of gravity) on an object near the surface of the earth is given by

F = mg

where m is the object's mass and g is the acceleration of objects near the surface of the earth.

The electric force on a charged object is given by

F = Eq

where E is the electric field at the point where the object is located and q is the charge of the object.

The weight (force of gravity) of a proton will act downwards (toward the surface of the earth), so in order for this force to be balanced, there must be an electric field pointing upward such that the electric force is equal and opposite to the weight. Set the magnitudes of the weight and electric force equal to each other:

mg = Eq

E = mg/q

Known values:

m = 1.67×10⁻27kg (a quick Google search will yield the mass of a proton)

g = 9.81m/s²

q = 1.60×10⁻19C

Plug in the known values and solve for E:

E = 1.67×10⁻27×9.81/(1.6×10⁻19)

E = 1.02×10⁻⁷N/C

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The doppler effect is when objects are not moving?<br><br> True <br><br> False
SVETLANKA909090 [29]

Answer:

reviewing the statement we can say that it is FALSE

Explanation:

The Doppler effect is the change in the perceived frequency of a sound wave by the RELATIVE MOTION of the source and the observer.

This effect is very useful for finding the speed of an object.

When reviewing the statement we can say that it is FALSE

6 0
2 years ago
A coating is being applied to reduce the reflectivity of a pane of glass to light with a wavelength of 522 nm incident near the
fredd [130]

Answer:

  t = 94.91 nm

Explanation:

given,

wavelength of the light = 522 nm

refractive index of the material  = 1.375

we know the equation

       c = ν λ

where ν is the frequency of the wave

           c is the speed of light

   \nu= \dfrac{c}{\nu\lambda}

   \nu = \dfrac{3\times 10^8}{522 \times 10^{-9}}

       ν = 5.75 x 10¹⁴ Hz

the thickness of the coating will be calculated using

        t = \dfrac{\lambda}{4\mu_{material}}

        t = \dfrac{522 \times 10^{-9}}{4\times 1.375}

              t = 94.91 nm

the thickness of the coating will be equal to t = 94.91 nm

7 0
3 years ago
An iron nail is driven into a block of ice by a single blow of a hammer. The hammerhead has a mass of 0.5 kg and an initial spee
larisa [96]

Answer:

The ice melts mass is:

m_g=7.6x10^{-3} g

Explanation:

Kinetic Energy  

K_E = 1/2*m*v^2

K_E = 1/2*0.5kg*(3.2m/s)^2

K_E=2.56 kg*m^2/s^2

Heat gained by ice= mass(g) x 80 cal

( 1 cal = 4.184 *10^7er or g cm^2/ sec^2)

Assuming no loss in heat,  in the motion so both continue with temperature 0~C

To find so the mass (gm) of ice melted

m_g= 1/2 *(0.5*1000)*(3.2m/s)^2* 100*100 / (80*4.184*10^7)

m_g=7.6x10^{-3} g

5 0
3 years ago
When Karl Kaveman adds chilled grog to his new granite mug, he removes 10.9 kJ of energy from the mug. If it has a mass of 625 g
mrs_skeptik [129]

Answer:

3°C

Explanation:

We can that heat Q=mc_p dT

Where m is the mass c_p = specific heat capacity

dT = Temperature difference

here we have given m=625 g =.625 kg

specific heat of granite =0.79 J/(g-K) = 0.79 KJ/(kg-k)

T_1 =25°C

T_2 we have to find

we have also given Q=10.9 KJ

10.9=0.625×0.79×(25-T_2)

25-T_2 =22

T_2=3°C

7 0
3 years ago
Read 2 more answers
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

for elastic collision we know that e = 1

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

v_{2f} - v_{1f} = 0 - 3.5

now by solving the two equation

56v_{2f} = 189

v_{2f} = 3.375 m/s

also we know that

v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s

so final speed of the nail is 6.875 m/s


6 0
2 years ago
Read 2 more answers
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