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ANTONII [103]
3 years ago
12

What is the strength of an electric field that will balance the weight of a proton?

Physics
1 answer:
alukav5142 [94]3 years ago
3 0

The weight (force of gravity) on an object near the surface of the earth is given by

F = mg

where m is the object's mass and g is the acceleration of objects near the surface of the earth.

The electric force on a charged object is given by

F = Eq

where E is the electric field at the point where the object is located and q is the charge of the object.

The weight (force of gravity) of a proton will act downwards (toward the surface of the earth), so in order for this force to be balanced, there must be an electric field pointing upward such that the electric force is equal and opposite to the weight. Set the magnitudes of the weight and electric force equal to each other:

mg = Eq

E = mg/q

Known values:

m = 1.67×10⁻27kg (a quick Google search will yield the mass of a proton)

g = 9.81m/s²

q = 1.60×10⁻19C

Plug in the known values and solve for E:

E = 1.67×10⁻27×9.81/(1.6×10⁻19)

E = 1.02×10⁻⁷N/C

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Andreas93 [3]

Answer:

The final energy is 1,700 J

Explanation: According to first law of thermodynamics:

=Final energy-initial energy=Change in internal energy

q = heat absorbed or released

w = work done by or on the system

w = work done by the system=  {Work done by the system is negative as the final volume is greater than initial volume}

q = +500J   {Heat absorbed by the system is positive}

w = work done by the system = -300J

Explanation:

5 0
4 years ago
For each of the following cases, indicate whether the net work done is positive, negative, or zero. (a) gravity acting on a fall
irina [24]

Answer:

Explanation:

We to indicate whether work is positive or negative or zero

Note, Work can be define as the produce of force and distance in the direction of the force, work is the dot product of force and displacement

W = F•d

(a) gravity acting on a falling ball

Work done acting on a falling ball is positive, since gravity does work on the ball. And g is positive downward.

Then, Work done by a free falling body is

W = mgh

(b) girl accelerating a wagon from rest

The workdone by a girl accelerating a wagon is positive

Since the wagon is a accelerating, then the velocity is increasing, then, the acceleration is positive

Work done by an accelerating car can be calculated be

W = F×d

Where the force is mass of the car times the positive acceleration

W = m•a•d

(c) a skydiver falling at terminal velocity through the air

The work done is zero since the terminal velocity is constant, so their is no change in velocity, the drag force is equal to the weight of the body and their is no external force acting on the body and the vertical acceleration goes to zero and since no acceleration, the work done is zero

W = m×a×h

W = 0J

But in this case, what is still don't by gravity. Since gravity is not zero.

(d) friction acting on a car so that it rolls to a stop.

The work done by friction is negative. This is due to the fact that the velocity of the car decreases with time and this implies that the car is decelerating, so the acceleration is negative, then,

W = m ×a × d

Since a =-ve

Then, W = —m•a•d

The work done by friction is negative

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kirill115 [55]

Answer:

I think the answer is D...

Explanation:

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Vlad1618 [11]

Answer:Image will be located at 2F on the other side of the lens.

Explanation:

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What is the weight of a 700 kg boat in Newton's?
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