Answer:
18 liters
Explanation:
Step 1: Figure out what the formula and what you are dealing with.
- 25 degrees celcius is constant, so it is irrelevant for the mathmatical part.
- P1 = 1 atm
- P2 = 20 atm
- V1 = 360 liters
- V2 = trying to find
Note: remember the original equation is V1/P1 = V2/P2
- Step 2: Rearrange the equation to fit this problem, you should get...
V2 = V1 x P1 / P2
- Step 3: Fill our own numbers in. You should get...
360 L x 1 atm / 20 atm = 18 Liters (do the math)
- Answer = 18 Liters
- Remember to just follow the formula and fill it in with your own numbers.
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Answer:
Option A. KCl (aq)
Option D. Mg(OH)₂(s
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
MgCl₂(aq) + KOH(aq) —>
In solution, MgCl₂(aq) and KOH(aq) will dissociate as follow:
MgCl₂(aq) —> Mg²⁺(aq) + 2Cl¯(aq)
KOH(aq) —> K⁺(aq) + OH¯(aq)
MgCl₂(aq) + KOH(aq) —>
Mg²⁺(aq) + 2Cl¯(aq) + 2K⁺(aq) + OH¯(aq) —> 2K⁺(aq) + 2Cl¯(aq) + Mg(OH)₂ (s)
MgCl₂(aq) + KOH(aq) —> 2KCl (aq) + Mg(OH)₂(s)
Thus, the products of the above reaction are: KCl(aq) and Mg(OH)₂(s)
Thus, option A and D gives the correct answer to the question.
<u>Given:</u>
Concentration of Ba(OH)2 = 0.348 M
<u>To determine:</u>
pOH of the above solution
<u>Explanation:</u>
Based on the stoichiometry-
1 mole of Ba(OH)2 is composed of 1 mole of Ba2+ ion and 2 moles of OH- ion
Therefore, concentration of OH- ion = 2*0.348 = 0.696 M
pOH = -log[OH-] = - log[0.696] = 0.157
Ans: pOH of 0.348M Ba(OH)2 is 0.157
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