Stoichiometry is the ratio of reactants to products in a balanced chemical reaction equation. the stoichiometry in this case of H₂ to O₂ is 2:1. This means that 2 moles of H₂ reacts with 1 mol of O₂. we have been asked to calculate the volume of H₂ gas. Since both O₂ and H₂ are gases, at standard conditions its stated that molar volume of gases is 22.4 L This means that at standard temperature and pressure, 1 mol of any gas occupies a volume of 22.4 L first we need to calculate the number of O₂ moles reacted; 22.4 L of gas - 1 mol of O₂ 1 L of gas - 1/22.4 mol/L then 20 L of O₂ - 1/22.4 mol/L * 20 L = 0.89 mol stoichiometry of H₂ to O₂ is 2:1 the number of H₂ moles = 0.89*2 = 1.79 mol 1 mol occupies 22.4 L Therefore 1.79 mol = 22.4 L/mol * 1.79 mol = 40 L Therefore it can be seen that stoichiometry applies to volumes as well. volume of H₂ : O₂ = 40 L : 20 L = 2:1 volume and moles both can be determined by stoichiometry. Volume of H₂ reacted = 40 L
If the sign is positive then the reaction is feasible and could take place. If it is negative it is not likely the reaction will take place as it is not feasible