Question

What is the mass of 2.25 moles of manganese(lv) sulfide(MnS2)

Answer 1

Hi! I'm hoping I understand your question correctly.. To calculate the mass or grams of MnS^2 you will have to find the molar mass. The molar mass is 87.003 g/mol. All you have to do is use stoichiometry and multiply that molar mass by the mols (2.25)! Hope this helped! Remember your sig figs, too!

Answer 2

Explanation:

Number of moles is defined as mass divided by molar mass of the substance or atom.

Mathematically,     No. of moles = $\frac{mass}{molar mass}$

It is known that molar mass of $MnS_{2}$ is 119.058 g/mol and number of moles is given as 2.25 mol.

Therefore, calculate mass of $MnS_{2}$ as follows.

                          No. of moles = $\frac{mass}{molar mass}$

                                   2.25 mol = $\frac{mass}{119.058 g/mol}$

                                 mass = 267.88 g

Thus, we can conclude that mass of 2.25 moles of manganese(lv) sulfide(MnS2) is 267.88 g.