What is the mass of 2.25 moles of manganese(lv) sulfide(MnS2)
2 answers:
Explanation:
Number of moles is defined as mass divided by molar mass of the substance or atom.
Mathematically, No. of moles =
It is known that molar mass of is 119.058 g/mol and number of moles is given as 2.25 mol.
Therefore, calculate mass of as follows.
No. of moles =
2.25 mol =
mass = 267.88 g
Thus, we can conclude that mass of 2.25 moles of manganese(lv) sulfide(MnS2) is 267.88 g.
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Answer:
6,97x10⁻³ gallons
Explanation:
pH is defined as:
pH = -log [H⁺]
Thus, you need to have, in the end:
10⁻⁷ = [H⁺]
And you have, in the first:
= [H⁺]
The volume of swimming pool is:
700'000 galllons × = 2649787 L
Thus, the moles of H⁺ in the first and in the end are:
First:
× 2649787L = 1,24x10⁻³ moles
End:
× 2649787L = 0,265 moles
Thus, the moles of H⁺ you need to add are:
0,265 - 1,24x10⁻³ = <em>0,26376 moles</em>
These moles comes from 10M HCl, thus, the volume in gallons you need to add are:
=
<em>6,97x10⁻³ gallons</em>
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I hope it helps!