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Stolb23 [73]
2 years ago
14

How many mL of a 0.375 M solution can be made from 35 g of calcium phosphate?

Chemistry
1 answer:
andrew11 [14]2 years ago
3 0

Answer:

300 mL

Explanation:

the unit formula of calcium phosphate is Ca3(PO4)2

molar mass of Ca3(PO4)2 = (3×40 + 2×31 + 8×16) g/mol = 310 g/mol

n = m/M = 35 g/(310 g/mol)

c = n/V

V = n/c = [35 g/(310 g/mol)]/0.375 mol/L

V = 0.30 L = 300 mL

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Aluminum foil is often incorrectly termed tin foil. If the density of tin is 7.28g/cm³,what is the thickness of a piece of tin f
leonid [27]

Answer:

15.0 µm

Step-by-step explanation:

Density = mass/volume

        D = m/V     Multiply each side by V

      DV = m        Divide each side by D

        V = m/D

Data:

m = 1.091 g

D = 7.28 g/cm³

 l = 10.0 cm

w = 10.0 cm

Calculation:

<em>(a) Volume of foil </em>

V = 1.091 g  × (1 cm³/7.28 g)

  = 0.1499 cm³

(b) <em>Thickness of foil </em>

The foil is a rectangular solid.

V  = lwh                            Divide each side by lw

h = V/(lw)

   = 0.1499/(10 × 10)

   = 1.50 × 10⁻³ cm           Convert to millimetres

   = 0.015 mm                  Convert to micrometres

   = 15.0 µm

The foil is 15.0 µm thick.

4 0
3 years ago
What is a property of a combustion reaction?
ohaa [14]
A, O2 has to be a reactant for combustion to burn
8 0
3 years ago
Calculate the standard cell potential at 25 ∘C for the reaction X(s)+2Y+(aq)→X2+(aq)+2Y(s) where ΔH∘ = -687 kJ and ΔS∘ = -169 J/
aivan3 [116]

Answer:

-0.129V

Explanation:

The change in free energy is obtained from the given parameters after which the value is now applied to obtain the cell potential in volts from the formukar shown in the solution below.

6 0
3 years ago
g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The h
Setler79 [48]

Answer:

6.88 mg

Explanation:

Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄

The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.

175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P

Step 2: Calculate the rate constant for the decay of ³²P

The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.

k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹

Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days

For first-order kinetics, we will use the following expression.

ln P = ln P₀ - k × t

ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d

P = 6.88 mg

3 0
3 years ago
Using the reaction C12H22O11 + 12 O2 -&gt;12CO2 + 11H2O (e). How many grams of carbon dioxide can be produced from 456.7g sucros
klio [65]

Answer:

704.6 g CO2

Explanation:

MM sucrose = 342.3 g/mol

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7 0
2 years ago
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