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2 years ago

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two investments earn an annual income of $645. an investment earns an annual simple interest rate of 7.7%, and the other investm

ent earns an annual simple interest rate of 6.9%. the total amount invested is $9000. how much is invested in each account?

1 answer:

Andreas93 [3]2 years ago

6 0

In how many months or years if just one month a little under 3000 each

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Does someone mind helping me with this question? Thank you!

alukav5142 [94]

Answer:

160 sq cm

Step-by-step explanation:

Since the two trapezoids are similar, you can use a ratio to find the area.

If we use x to represent the area of ABCD, then the ratio will look something like:

5/20 = 40/x

which then we can solve x to be 160 sq cm.

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1 year ago

there are 12 grams of protein 2 ounces of almonds write if the relationship is propotional if so write an equation for the relat

Elza [17]

There are 12 grams of protein 2 ounces of almond write if the relationship is proportional if so write an equation for the relationship.
12=2
6=1

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2 years ago

The product of 1 1/2 and 2 is less than, equal to, or greater than 2

Rus_ich [418]

Answer:

The answer is 1 1/2 < 2

Step-by-step explanation:

If we convert 1/2 into a decimal, we would get .5. Add that to 1 and we get 1.5. Therfore, 2 > 1.5

3 0

2 years ago

Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1

weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

$f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})$

This gives

$f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})$

Evaluate the products

$f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})$

Evaluate the like terms

$f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}$

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

7 0

1 year ago

In class A, John got 85 for his first test John's class mean was 75 and standard deviation was 5. In class B, Kathy got 80 in he

ivanzaharov [21]

Answer:

b. Kathy

Step-by-step explanation:

We compare each of their score by how far away from the mean when in term of the standard deviation. Using the following formula

$\frac{x - \mu}{\sigma}$

For John he is (85 - 75)/5 = 2.

For Kathy she is (80 - 50)/10 = 3.

Since Kathy is 3 standard deviation better than her class' average, while John is only 2's. We conclude that Kathy did better.

6 0

2 years ago