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Natasha_Volkova [10]
3 years ago
7

Write conversion factors (as ratios) for the number of:

Chemistry
1 answer:
nignag [31]3 years ago
3 0
The answer is C, grams in 1 ounce, I am pretty sure.
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What is the volume of 0.284g of carbon dioxide at STP ??
coldgirl [10]

Answer:

Explanatio

NCO2= 0, 248 /44= 0 ,005636

VCO2=  0,005636* 22,4= 0 ,126254545

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Murrr4er [49]

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Explanation:

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3 0
3 years ago
Read 2 more answers
PLZ HELP ASAP!!!!!
aleksley [76]
C. 346 g hope this helps you
4 0
3 years ago
Perform the following conversions:
spayn [35]

0 K in Celsius scale is -273 degree Celsius and in Fahrenheit scale 459 degree F.

The degree of a body's heat or cold is referred to as the gas's temperature. It is stated in temperature units such as, degree Celsius, Fahrenheit  and Kelvin these temperature units are interchangeable. To convert Celsius to Fahrenheit ° F = 9/5 ( ° C) + 32, kelvin to Fahrenheit= ° F = 9/5 (K - 273) + 32, Celsius to kelvin K = ° C + 273.  to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32)  In this question,  to convert Fahrenheit to Celsius ° C = 5/9 (° F - 32) = 0-273 K (5/9 - F-32) =459 degree F. and kelvin to Celsius K - 273 = C = -273 degree Celsius

At 8^0C K= 8 + 273 =281 degree Celsius and at 8F , 8= 9/5(k-273) +32 =453 F

To learn more about Fahrenheit and Celsius:

brainly.com/question/1844449

#SPJ4

5 0
1 year ago
Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
djyliett [7]
Ok first, we have to create a balanced equation for the dissolution of nitrous acid.

HNO2 <-> H(+) + NO2(-)

Next, create an ICE table

           HNO2   <-->  H+        NO2-
[]i        0.230M          0M       0M
Δ[]      -x                   +x         +x
[]f        0.230-x          x           x

Then, using the concentration equation, you get

4.5x10^-4 = [H+][NO2-]/[HNO2]

4.5x10^-4 = x*x / .230 - x

However, because the Ka value for nitrous acid is lower than 10^-3, we can assume the amount it dissociates is negligable, 

assume 0.230-x ≈ 0.230

4.5x10^-4 = x^2/0.230

Then, we solve for x by first multiplying both sides by 0.230 and then taking the square root of both sides.

We get the final concentrations of [H+] and [NO2-] to be x, which equals 0.01M.

Then to find percent dissociation, you do final concentration/initial concentration.

0.01M/0.230M = .0434 or 

≈4.34% dissociation.
8 0
3 years ago
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