Calculate the percent ionization of nitrous acid in a solution that is 0.230 M in nitrous acid. The acid dissociation constant o
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We can divide this problem into 4 steps:
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x
=1005 g soln
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L
Here we have to choose the molecule which can generate ion-dipole interaction with ammonia.
The NH₃ will have ion dipole interaction only with b) NaOH.
a) The OCl₂ molecule is highly unstable and remains in a linear state as shown in the figure.
b) The NaOH is purely an ionic compound. There is one lone pair of electron on the nitrogen (N) atom of ammonia and also the N-H bond has dipole moment. Now among the given molecules only NaOH is ionic in nature which remains as Na⁺ and OH⁻. Thus we can expect an ion-dipole interaction between these molecules, it is shown in the figure.
c) SiO₂ is purely an covalent compound the structure is shown in the figure.
d) Methyl iodide (CH₃I) is also a covalent compound.
e) The butanol (C₄H₉OH) is a covalent compound.
So we may expect only ion-dipole interaction with b) NaOH.
