A gas is most likely to exist at which of the following conditions?
2 answers:
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Taking into account the reaction stoichiometry, 8.8488 grams of (NH₄)₃PO₄ is produced by the reaction of 5.82g of phosphoric acid.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
H₃PO₄ + 3 NH₃ → (NH₄)₃PO₄
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₃PO₄: 1 mole
- NH₃: 3 moles
- (NH₄)₃PO₄: 1 mole
The molar mass of the compounds is:
- H₃PO₄: 98 g/mole
- NH₃: 17 g/mole
- (NH₄)₃PO₄: 149 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- H₃PO₄: 1 mole ×98 g/mole= 98 grams
- NH₃: 3 moles ×17 g/mole= 51 grams
- (NH₄)₃PO₄: 1 mole ×149 g/mole= 149 grams
The following rule of three can be applied: if by reaction stoichiometry 98 grams of H₃PO₄ form 149 grams of (NH₄)₃PO₄, 5.82 grams of H₃PO₄ form how much mass of (NH₄)₃PO₄?
mass of (NH₄)₃PO₄=
<u><em>mass of (NH₄)₃PO₄= 8.8488 grams</em></u>
Finally, 8.8488 grams of (NH₄)₃PO₄ is produced by the reaction of 5.82g of phosphoric acid.
Learn more about the reaction stoichiometry:
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Answer:
Explanation:
To find the number of moles of each element present in 1 mole of Be(OH)₂, we use the ratio of the molar masses of the elements to the compound and multiply by the given mole.
Molar mass of Be(OH)₂ = 9 + 2(16+1) = 43g/mol
number of moles of Be = x 1 = 0.209mole
number of moles of O = x 1 = 0.744mole
number of moles of H = x 1 = 0.047mole
Answer: 46.6 grams
Explanation:
Given : density of hexane = 0.660 g/ml
volume of hexane = 20 ml
Mass of hexane =
moles of hexane =
According to stoichiometry :
2 moles of hexane reacts with 19 moles of oxygen
Thus 0.14 moles hexane will react with = moles of oxygen
Mass of oxygen =
Thus minimum mass of oxygen required for the complete reaction of 20.0 mL of hexane is 46.6 grams.