Answer:
Klorina's rate in still water is 4.5 km/h
Current's rate is 0.5 km/h
Step-by-step explanation:
Let
x km/h = Klorina's rate in still water
y km/h = current's rate
<u>With the current (current helps):</u>
Distance = 10 km
Time = 2 hours
Rate = x + y km/h
<u>Against the current:</u>
Distance = 8 km
Time = 2 hours
Rate = x - y km/h
Divide both equations by 2:
Add these equations:
Subtract these two equations:
Your sequence appears to be geometric with a common ratio of 2. It can be described by
a(n) = (-2 2/3)·2^(n-1)
_____
This can be written in a number of other forms, including
a(n) = (-8/3)·2^(n-1)
a(n) = (-1/3)·2^(n+2)
a(n) = (-4/3)·2^n
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[1585y+796z] totally answer
Answer: 64 years
Step-by-step explanation:
Let assume the dealer sold the bottle now for $P, then invested that money at 5% interest. The return would be:
R1 = P(1.05)^t,
This means that after t years, the dealer would have the total amount of:
$P×1.05^t.
If the dealer prefer to wait for t years from now to sell the bottle of wine, then he will get the return of:
R2 = $P(1 + 20).
The value of t which will make both returns equal, will be;
R1 = R2.
P×1.05^t = P(1+20)
P will cancel out
1.05^t = 21
Log both sides
Log1.05^t = Log21
tLog1.05 = Log21
t = Log21/Log1.05
t = 64 years
The best time to sell the wine is therefore 64years from now.
