Answer:
Keith has 4 pennies, 3 dimes and 2 nickels.
Step-by-step explanation:
Let the pennies be = p
Let the nickels be = n
Let the dimes be = d
Total coins Keith has = 9
So, 1st equation form :
....(1)
Keith has one more dime than nickels, means .....(2)
Total value of these coins is $0.44
So, third equation forms:
.....(3)
Substituting (2) in (1)
.....(4)
Similarly substitution (2) in (3)
....(5)
Now multiplying (4) by 0.01 and subtracting by (5)
subtracting this from (5) we get
So, we get n = 2
p = 4
d = 3
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Therefore, Keith has 4 pennies, 3 dimes and 2 nickels.