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djyliett [7]
3 years ago
13

What do binary ionic compounds, binary molecular compounds, and binary acids have in common?

Chemistry
1 answer:
Fudgin [204]3 years ago
8 0
Essentially the term binary, meaning each different thing has two components. Binary ionic compounds have two ionic compounds, binary molecular compounds have two molecular compounds, and binary acids have two acids.
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Given that nitrogen forms three bonds with hydrogen to make <img src="https://tex.z-dn.net/?f=NH_%7B3%7D" id="TexFormula1" title
lbvjy [14]

Answer:

Three hydrogen atoms to form PH₃.

Explanation:

Hello!

In this case, since the elements belonging to the nitrogen family (N, P, As, Sb and Bi) show five valence electrons, because there are five electrons at their outer shell, it is clear that if phosphorous bonds with hydrogen, it is going to require the same amount of oxygen atoms (3) because elements having five valence electrons need 3 bonds in order to attain the octet (5+3=8).

Therefore the compound would be:

PH_3

Which is phosphine.

Best regards!

3 0
3 years ago
The temperature of a gas is 30 degrees Celsius and its pressure is 760 torr. If the temperature originally
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T₁ = 40°C + 273.15 = 313.15 Kelvin T₂ = 30°C + 273.15 = 303.15 Kelvin

Solving Gay-Lussac's Law for P₁ we get:
P₁ = P₂ • T₁ ÷ T₂ P₁ = 760 torr • 313.15 K ÷ 303.15 K P₁ = 785.07 torr

Using the calculator, we click on the P1 button.
We then enter the 3 numbers 760 313.15 and 303.15 into the correct boxes then click "CALCULATE" and get our answer of 785.07 torr.
6 0
3 years ago
Consider the electrolysis of aqueous agno3. Refer to the table of standard reduction potentials as needed. What should form at t
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Answer:

Ag+

Explanation:

anode: 2AgNO3(l)⟶Ag(aq)+NO3(g)

8 0
3 years ago
What is the Pauli Exclusion Principle?
Fiesta28 [93]

Answer:

the answer is A An atomic orbital can only hold a maximum of 2 electrons, each with opposite spins

Explanation:

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An ideal gas in a sealed container has an initial volume of 2.80 L. At constant pressure, it is cooled to 18.00 °C, where its
Aleks04 [339]

Answer:

T_1=-91.18\°C

Explanation:

Hello there!

In this case, given the T-V variation, we understand it is possible to apply the Charles' law as shown below:

\frac{T_1}{V_1}= \frac{T_2}{V_2}

Thus, since we are interested in the initial temperature, we can solve for T1, plug in the volumes and use T2 in kelvins:

T_1= \frac{T_2V_1}{V_2}\\\\T_1= \frac{(18.00+273.15)K(1.75L)}{(2.80L)}\\\\T_1=182K-273.15\\\\T_1=-91.18\°C

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