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3 years ago

How much has CO2 in the atmosphere increased since the Industrial Revolution?

Chemistry

1 answer:

leva [86]3 years ago

8 0

Answer:

The concentration of carbon dioxide in the atmosphere has increased more in the northern hemisphere where more fossil fuel burning occurs. Since the Industrial Revolution the concentration globally has increased by about 40 % .

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If 5.0 g of each reactant were used for the the following process, the limiting reactant would be: 2KMnO4 + 5Hg2Cl2 + 16HCl -&gt

IceJOKER [234]

Answer:

The limiting reactant is Hg2Cl2.

Explanation:

Step 1: Data given

Mass of each reactant = 5.0 grams

KMnO4 MM=158 g/mol

Hg2Cl2 MM=472.1 g/mol

HCl MM=36.5 g/mol

HgCl2 MM=271.5 g/mol

MnCl2 MM=125.8 g/mol

KCl MM=74.6 g/mol

H2O MM=18 g/mol)

Step 2: The balanced equation

2KMnO4 + 5Hg2Cl2 + 16HCl -> 10HgCl2 + 2MnCl2 + 2KCl + 8H2O

Step 3: Calculate moles

KMnO4 = 5.00 grams / 158 g/mol = 0.0316 mol

Hg2CL2 = 5.00 grams / 472.1 g/mol = 0.0106 mol

HCl = 5.00 grams / 36.5 g/mol = 0.137 mol

Step 3: Calculate limiting reactant

For 2 moles of KMno4 we need 5 moles of Hg2Cl2 and 16 moles of HCl

Hg2Cl2 has the smallest amount of moles.

For 5 moles Hg2Cl2 ( 0.0106 mol) we need 0.0106 / (5/2) = 0.00424 mol KMnO4

For 5 moles Hg2Cl2 we need (16/5) *0.0106 = 0.03392 moles of HCl

So the limiting reactant is Hg2Cl2.

Step 4: Calculate moles of product produced:

2*0.0106 = 0.0212 moles of HgCl2

(2/5) * 0.0106 = 0.00424 moles of MnCl2 and 0.00424 moles of KCl

(8/5) * 0.0106 = 0.01696 moles H2O

7 0

3 years ago

MOLE TO ATOM CONVERSIONS

Advocard [28]

Answer:

Answers are given below.

Explanation:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1) 0.680 moles of H₂S

0.680 mol × 6.022 × 10²³ molecules / 1mol

4.09× 10²³ molecules

2) 8.96 moles of KI

8.96 mol × 6.022 × 10²³ molecules / 1mol

53.96 × 10²³ molecules

3) 6.500 moles of KClO

6.500 mol × 6.022 × 10²³ molecules / 1mol

39.143 × 10²³ molecules

4) 0.950 moles of NaOH

0.950 mol × 6.022 × 10²³ molecules / 1mol

5.721 × 10²³ molecules

5) 4.73 moles of Na₂CO₃

4.73 mol × 6.022 × 10²³ molecules / 1mol

28.48 × 10²³ molecules

7 0

3 years ago

Isotopes of the same element differ in their ____.

Zarrin [17]

<span>Isotopes of the same element differ in their "Atomic masses"

Hope this helps!</span>

5 0

4 years ago

How many moles are in 5.25 L of oxygen gas as stp

Masteriza [31]

Answer:

The correct answer is 0, 235 mol

Explanation:

We use the formula PV =nRT. The normal conditions of temperature and pressure are 273K and 1 atm, we use the gas constant = 0, 082 l atm / K mol:

1 atm x 5, 25l = n x 0, 082 l atm / K mol x 273 K

n= 1 atm x 5, 25l /0, 082 l atm / K mol x 273 K

n= 0, 235 mol

8 0

3 years ago

Constructive and destructive process.

Aleks [24]

Answer:

again here

Explanation:

Collection and analysis of data indicate that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion. I can explain how constructive and destructive forces affect the nature of landforms on Earth.

Please mark as brainliest

8 0

3 years ago