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AysviL [449]
3 years ago
12

How much has CO2 in the atmosphere increased since the Industrial Revolution?

Chemistry
1 answer:
leva [86]3 years ago
8 0

Answer:

The concentration of carbon dioxide in the atmosphere has increased more in the northern hemisphere where more fossil fuel burning occurs. Since the Industrial Revolution the concentration globally has increased by about 40 % .

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Please help me with this Science Worksheet
s2008m [1.1K]
I’m not 100% sure on the physical one but this is what I think

Physical
1- sunlight
2- sparks
3- burns
4- wood
5- light

Chemical
6- heat
7- ice
8- water
9- evaporates
10- vaper

Hope this helps :)
4 0
2 years ago
a compound has a percent compostion of carbon equal to 48.8383%, hydrogen equal to 8.1636%, and oxygen equal to 43.1981%. what i
Margarita [4]

Answer:

C₂H₃O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 48.8383%

Hydrogen (H) = 8.1636%

Oxygen (O) = 43.1981%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 48.8383%

H = 8.1636%

O = 43.1981%

Divide by their molar mass

C = 48.8383 / 12 = 4.07

H = 8.1636 / 1 = 8.1636

O = 43.1981 / 16 = 2.7

Divide by the smallest

C = 4.07 / 2.7 = 2

H = 8.1636 / 2.7 = 3

O = 2.7 /2.7 = 1

Thus, the empirical formula of the compound is C₂H₃O

8 0
3 years ago
How can the actions of people affect runoff and absorption in a positive way? How do they affect them in a negative way?
lora16 [44]

Answer:

pollution and waste every where like in are ouceans

Explanation:

4 0
2 years ago
The two products that are formed when a solution of HNO3 and a solution of NaOH react are water and:
solniwko [45]

Answer:  NaNO3 (Sodium Trioxonitrate (V) )

Explanation:

The equation of the reaction is; HNO3 + NaOH -----> H2O + NaNO3

7 0
3 years ago
Read 2 more answers
If the point of the nail can be approximated as a circle with a radius 2.00×10^-3m What is the pressure in MPa exerted on the wa
Natasha_Volkova [10]

Answer:

8.28 MPa

Explanation:

From the question given above, the following data were obtained:

Radius (r) = 2×10¯³ m

Force applied (F) = 104 N

Pressure (P) =?

Next, we shall determine the area of the nail (i.e circle). This can be obtained as follow:

Radius (r) = 2×10¯³ m

Area (A) of circle =?

Pi (π) = 3.14

A = πr²

A = 3.14 × (2×10¯³)²

A = 3.14 × 4×10¯⁶

A = 1.256×10¯⁵ m²

Next, we shall determine the pressure. This can be obtained as follow:

Force applied (F) = 104 N

Area (A) = 1.256×10¯⁵ m²

Pressure (P) =?

P = F / A

P = 104 / 1.256×10¯⁵

P = 8280254.78 Nm¯²

Finally, we shall convert 8280254.78 Nm¯² to MPa. This can be obtained as follow:

1 Nm¯² = 1×10¯⁶ MPa

Therefore,

8280254.78 Nm¯² = 8280254.78 Nm¯² × 1×10¯⁶ MPa / 1 Nm¯²

8280254.78 Nm¯² = 8.28 MPa

Thus, the pressure exerted on the wall is 8.28 MPa

3 0
3 years ago
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