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Komok [63]
3 years ago
13

Touching a hot stove or the melting of ice in your hand (as you squeeze it) is an example of

Chemistry
2 answers:
aivan3 [116]3 years ago
6 0

Answer: conduction

Explanation:

the heat passes out of the stove and into your hand. So is holding an ice cube – the heat is conducted out of your hand, and into the ice cube (that’s why your hand feels cold).

torisob [31]3 years ago
3 0

Answer:

Conduction

Explanation:

Conduction occurs when objects touch. The heat from the warmer object is transferred to the cooler object, eventually evening out the temperatures.

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Which statement accurately describes a potential danger of radiation?
dsp73

Answer:

Even small amounts of radiation over a prolonged period of time can be dangerous.

Explanation:

We all get exposed to radiation, such as through x-rays, and it's fine as one off experiences. However, if you're constantly dealing with radiation without any sort of protection, no matter how small the amount is, it could potentially lead to consequences like cancer. This is due to the fact that radiation can alter our genes

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3 years ago
How many protons and neutrons does br-1 have
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35 protons 35 electrons and 45 nutrons
5 0
4 years ago
Water is able to travel up stems to leaves in a plant. this is an example of _____
Anastasy [175]
Your answer should be B :)
5 0
3 years ago
To prepare 300.0 ml of 0.2 m nacl how many grams of nacl should be weighed out?
Leokris [45]
One mole of NaCl weighs 58.44 grams
Therefore 1L of one mole of NaCl contains 58.44 grams
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8 0
3 years ago
Two moles of a monatomic ideal gas are contained at a pressure of 1 atm and a temperature of 300 K; 34,166 J of heat are transfe
anygoal [31]

Answer:

Final temperature is 302 K

Explanation:

You can now initial volume with ideal gas law, thus:

V = \frac{n.R.T}{P}

Where:

n are moles: 2 moles

R is gas constant: 0,082 \frac{atm.L}{mol.K}

T is temperature: 300 K

P is pressure: 1 atm

V is volume, with these values: <em>49,2 L</em>

The work in the expansion of the gas, W, is: 1216 J - 34166 J = <em>-32950 J</em>

This work is:

W = P (Vf- Vi)

Where P is constant pressure, 1 atm

And Vf and Vi are final and initial volume in the expansion

-32950 J = -1 atm (Vf-49,2L) × \frac{101325 J}{1 atm.L}

Solving: <em>Vf = 49,52 L</em>

Thus, final temperature could be obtained from ideal gas law, again:

T = \frac{P.V}{n.R}

Where:

n are moles: 2 moles

R is gas constant: 0,082 \frac{atm.L}{mol.K}

P is pressure: 1 atm

V is volume: 49,52 L

T is final temperature: <em>302 K</em>

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I hope it helps!

4 0
3 years ago
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