Answer:
2
Explanation:
CO₂ shows that there are 2 oxygen molecules. Also, the name Carbon Dioxide. This shows there is One Carbon and Two Oxygen molecules from the naming system.
Answer:
99.24%.
Explanation:
- NaCl reacted with AgNO₃ as in the balanced equation:
<em>NaCl + AgNO₃ → AgCl(↓) + NaNO₃,</em>
1.0 mol of NaCl reacts with 1.0 mol of AgNO₃ to produce 1.0 mol of AgCl and 1.0 mol of NaNO₃.
- We need to calculate the no. of moles of AgCl produced:
no. of moles of AgCl = mass/molar mass = (2.044 g)/(143.32 g/mol) = 0.0143 mol.
- Now, we can calculate the no. of moles of NaCl that can precipitated as AgCl (0.0143 mol), these moles represents the no. of moles of pure NaCl in the sample:
<em>using cross multiplication:</em>
1.0 mol of NaCl produce → 1.0 mol of AgCl, from the stichiometry.
∴ 0.0143 mol of NaCl produce → 0.0143 mol of AgCl.
- Now, we can get the mass of puree NaCl in the sample:
mass of pure NaCl = (no. of moles of pure NaCl)(molar mass of NaCl) = (0.0143 mol)(58.44 g/mol) = 0.8357 g.
∴ The percentage of NaCl in the impure sample = [(mass of pure NaCl)/(mass of the impure sample)] x 100 = [(0.8357 g)/(0.8421 g)] x 100 = 99.24%.
Answer:
a. Values are - (1) 3,1,-1,1/2 (2) 2,1,-1,-1/2 (3) 3,0,0,1/2 (4) 4,3,3,-1/2
(5) 3,2,2,1/2
b. Order be- I > Sn > Xe
Explanation:
a.
Valid quantum numbers are -
'l' value should be less than 'n' value and 'ml' value should be '-l' to 'l'
'ml' value should not more than 'l' or 'n'.
Values are -
3,1,-1,1/2
2,1,-1,-1/2
3,0,0,1/2
4,3,3,-1/2
3,2,2,1/2
b.
Given that-
I [Kr]4d¹⁰5s²5p⁵
Sn [Kr]4d¹⁰5s²5p²
Xe [Kr]4d¹⁰5s²5p⁶
Order be-
I > Sn > Xe
Xe is least because it is completely filled outer shell (5s²5p⁶