There is no diagram attached but there are some ways by which you can find it too easily by yourself
Usually energy diagram uses ∆H .
So
- If ∆H is +ve means reaction is exothermic and energy is released
- If ∆H is -ve means reaction is endothermic and energy is absorbed
So observe∆H whether it. is decreasing or increasing ,
- If increasing then energy is being released and vice versa
Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
There 3 elements wich is
C =4
H=8
O=4
So the total atoms are 16
Answer:

Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Assemble all the data in one place, with molar masses above the formulas and other information below them.
Mᵣ: 58.44
NaCl + AgNO₃ ⟶ NaNO₃ + AgCl
m/g: 0.245
V/mL: 50.
c/mmol·mL⁻¹: 0.0180
2. Calculate the moles of each reactant

3. Identify the limiting reactant
Calculate the moles of AgCl we can obtain from each reactant.
From NaCl:
The molar ratio of NaCl to AgCl is 1:1.

From AgNO₃:
The molar ratio of AgNO₃ to AgCl is 1:1.

AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.
4. Calculate the moles of excess reactant
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
I/mmol: 0.900 4.192 0
C/mmol: -0.900 -0.900 +0.900
E/mmol: 0 3.292 0.900
So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.
5. Calculate the concentration of Cl⁻
![\text{[Cl$^{-}$] } = \dfrac{\text{3.292 mmol}}{\text{50. mL}} = \textbf{0.066 mol/L}\\\text{The concentration of chloride ion is $\large \boxed{\textbf{0.066 mol/L}}$}](https://tex.z-dn.net/?f=%5Ctext%7B%5BCl%24%5E%7B-%7D%24%5D%20%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B3.292%20mmol%7D%7D%7B%5Ctext%7B50.%20mL%7D%7D%20%3D%20%5Ctextbf%7B0.066%20mol%2FL%7D%5C%5C%5Ctext%7BThe%20concentration%20of%20chloride%20ion%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.066%20mol%2FL%7D%7D%24%7D)
Answer:
Starting from your own home is the best way to reduce plastic pollution. You can reduce it by stop using plastic bags, water bottles, anything that is plastic. You can reuse things instead. Use less energy. Turn off the lights whenever you leave the house or if you aren't using it. Lastly, conserve water. Don't let the water running if you aren't using it.
Hope this helps! :)